Slowbus
Trainee
Firstly, please go easy as I'm still a trainee! Working on my L3 2365
I'm having trouble understanding the rationale behind adiabatics calculations for CPCs, because it seems to me that if you had a fault close to the CU on a longer circuit, or a fault on a short (in length) circuit, you'd have a very low Zs that would fail the equation in lots of instances.
Say, for example, you have a lighting circuit in 1.5mm T&E that is 20m long, protected by a 6A MCB. Let's say Ze is 0.35Ω, and we can calculate that R1+R2 is 0.6Ω via Table I1 in OSG. So expected Zs is 0.95Ω, and PFC is 242A.
If we plug it into the Adiabatic with 0.1s* then we get: sqrt(242 * 242 * 0.1) / 115 = 0.66Ω min CSA required - all good!
But, what if the fault occurs just 2m into the circuit? Nail through a cable etc.
Suddenly, the Zs is down at 0.41Ω, the PFC is up to 561A, and if you do the adiabatic it reckons you need 1.54mm on the CPC (yes, I know 7671 table 54.7 caps it at the line conductor CSA, but still)
Or, what if you had a short-length circuit (say 2m) - how would you get it to comply without using much beefier cables - and how does that make sense?
Am I missing something here, or doing my calculations wrong? What's the point in doing this overheat calculation only for the end of the cable, when a fault part-way along will likely fail it and the CPC overheat in the duration before the OCPD triggers?
*I've used 0.1s from the graph of a 60898 breaker, but most discussion of adiabatics uses the earthing arrangement timings - e.g. 0.4s for a final on TN system, which makes the requirements much harder to reach. Not fully sure which I should be using.
I'm having trouble understanding the rationale behind adiabatics calculations for CPCs, because it seems to me that if you had a fault close to the CU on a longer circuit, or a fault on a short (in length) circuit, you'd have a very low Zs that would fail the equation in lots of instances.
Say, for example, you have a lighting circuit in 1.5mm T&E that is 20m long, protected by a 6A MCB. Let's say Ze is 0.35Ω, and we can calculate that R1+R2 is 0.6Ω via Table I1 in OSG. So expected Zs is 0.95Ω, and PFC is 242A.
If we plug it into the Adiabatic with 0.1s* then we get: sqrt(242 * 242 * 0.1) / 115 = 0.66Ω min CSA required - all good!
But, what if the fault occurs just 2m into the circuit? Nail through a cable etc.
Suddenly, the Zs is down at 0.41Ω, the PFC is up to 561A, and if you do the adiabatic it reckons you need 1.54mm on the CPC (yes, I know 7671 table 54.7 caps it at the line conductor CSA, but still)
Or, what if you had a short-length circuit (say 2m) - how would you get it to comply without using much beefier cables - and how does that make sense?
Am I missing something here, or doing my calculations wrong? What's the point in doing this overheat calculation only for the end of the cable, when a fault part-way along will likely fail it and the CPC overheat in the duration before the OCPD triggers?
*I've used 0.1s from the graph of a 60898 breaker, but most discussion of adiabatics uses the earthing arrangement timings - e.g. 0.4s for a final on TN system, which makes the requirements much harder to reach. Not fully sure which I should be using.
- TL;DR
- Faults near CU or on very short circuits generally fail the adiabatic equation due to low Zs. Am I calculating wrong, or is this just "how it is"? If so, why bother at all?