S
speedtronic
In case of differential protection, say for generator, we know that current entering a phase must be equal to current leaving that phase. Now for example, there is a short cct between phase R & y at the point where current is entering the phase, just after CTs. So, now what will cause diff protection to operate? I mean due to short cct, will the current leaving these two phases will become zero? Which CTs will face maximum current, ones near the fault point or the others?
Will the current will flow in the reverse direction from the point where this short cct has happend? Please explain
Will the current will flow in the reverse direction from the point where this short cct has happend? Please explain
