Hi can sombody please shed some light on this for me i cant get my head round the process ?
this is the equation i've been given
a 230v 12.5kw domestic cooker maximum demand current I=p/v =12500/230=54.35
i understand that bit but its this bit i dont get
applying diversitiy
first 10a of full load current =10A =44.35
+30% of remaining = 44.35 x 30% =13.35
+5a for socket outlet = 5A
TOTAL = 28.3
Can some one please explain to me how you get 28.3 from the original 54.35 ??????????
this is the equation i've been given
a 230v 12.5kw domestic cooker maximum demand current I=p/v =12500/230=54.35
i understand that bit but its this bit i dont get
applying diversitiy
first 10a of full load current =10A =44.35
+30% of remaining = 44.35 x 30% =13.35
+5a for socket outlet = 5A
TOTAL = 28.3
Can some one please explain to me how you get 28.3 from the original 54.35 ??????????