I’m no expert on this, but do like to understand things, and know it’s to do with using a ‘balanced signal’ for low-noise transmission.
On each pair, there is a +ve-going and -ve-going signal, with only the difference them being detected at the far end. If there’s external noise induced on the line, it will usually appear on both wires equally, so remains undetected, as any noise waveform simply provides a signal on both wires equally, not affecting the difference signal. Result: a magically clean signal in a noisy environment!
The twisting reduces cross-talk between pairs in a multi-pair cable. Consider if, due to the extreme proximity of all those little wires, one of a pair might receive a larger crosstalk signal that its partner, it will be unbalanced, affecting the difference signal and so be resolved at the other end as noise, messing up fast data comms.
But if the pairs are twisted, the crosstalk hits one strand first for a bit, then the other for a bit, and so on. Therefore the crosstalk signal is magically applied to each pair’s partner equally. It then ‘looks’ like external noise at the other end and is unresolved.
Twist frequency differs so that different pairs don’t keep crossing at the same points again and again, reducing the cancellation effect.
Clever ennit?
I think I've got that essentially right, but if there are any comms network designers on here who know better, please take over!
(cf. Balanced professional microphone cabling using 3-pin XLR connectors and shielded two-core interconnects).
As being a bit of a data and as it happens live sound guru myself I can only agree with you. What you are saying is dead correct.