help with a calc

[The Ranger]

Say I have a circuit that pulls 16A @ 24V how do i work out the ratio for the load at 230V?


Thanks

 

[telectrix]

230/24 might be a good guess.

 

[The Ranger]

230/24 might be a good guess.

can't see how as that'll be voltage divided by voltage how would i acquire the load from that?

 

[telectrix]

16 x 24/230 = 1.67A. come on mate, not above secondary school , this one.

 

[ackbarthestar]

If we are talking linear transformer ratios then,

Power in = power out (+ losses, although less than 8% in most cases)
so
Vp.Ip = Vs.Is

Transform to give:

Vp/Vs = Is/Ip

therefore

250/25 = 15/Ip

Ip = 15/(250 * 25)

= 15/10 = 1.5A
or

250/25 = 10

or a voltage turns ratio of 10:1

You now substitute your own numbers

 

[balbecdaze]

I'll flesh it out if you like, the circuit uses POWER, P=IxV. So your 16A @ 24V is 384W. (P=16x24). The new voltage generates the same power, so 384=Ix230. I=384/230=1.67A

 

[balbecdaze]

Doh! cross posting with a better answer AGAIN!