So I've calculated my hotel lighting and 1 circuit has an (ib) of 0.33a and I put a 6a breaker on it (in) then got my (iz) 5.8a which is suppose to be equal to (in) or greater right but it's not so what should I do to change this. By the way my (ca) is 1.03 my (cg, ci, cf,) are all 1. Please explain to me in a simple basic way. Thanks guys ?