Assuming same size neutral cable as lines cables... my understanding was that a line-line fault current would be sqrt(3) times the L-N PSCC; but a symmetrical fault would be 2 times the L-N PSCC. However I've never seen a convincing set of maths to verify this. There are hints of it in this link... but "Z" is ill-defined there, and there seems to be a factor of 2 out.
Question: would a single phase circuit breaker in a 3-phase board ever have to deal with a symmetric fault? A 3-phase breaker, sure (perhaps a broken star-delta starter?). Because I've seen situations where sqrt(3) x PSCC is on the "ok" side of the line, whereas 2 x PSCC is more on the "explody fireball of doom" side...
Question: would a single phase circuit breaker in a 3-phase board ever have to deal with a symmetric fault? A 3-phase breaker, sure (perhaps a broken star-delta starter?). Because I've seen situations where sqrt(3) x PSCC is on the "ok" side of the line, whereas 2 x PSCC is more on the "explody fireball of doom" side...