Not electrical but I need some maths help.

[Bobster]

Trying to work out how much air M^3/min an airline will be releasing to atmosphere.

I've searched google and can't really find a formula I can use without going massively in depth with it. I only want a fairly accurate rough answer.

Can anyone help.


Heres some information:

The airline is 1/4inch, it's got a length of 30m. It's currently venting to atmosphere effectively and the air pressure is at 10bar.

Might be a long shot but worth a try.

 

[topquark]

About 0.25M^3 per min.

 

[Bobster]

Cheers top quark, how did you go about working that out?

 

[topquark]

Simply used an online calculator that gave me 9.46 CFM and converted it to cubic meters per min. To be fair it does make certain assumptions about being at standard temperature and assumes no bends in the pipe at all and no heating effect in the pipe from the air flow. Then you did say rough answer.

Calculator at: Compressed Air Flow Chart | Compressed Air Systems | Selecting Compressed Air System

Actual results were: 9.46 CFM which gives 0.2678774 CM/M

 

[telectrix]

Simply used an online calculator that gave me 9.46 CFM and converted it to cubic meters per min. To be fair it does make certain assumptions about being at standard temperature and assumes no bends in the pipe at all and no heating effect in the pipe from the air flow. Then you did say rough answer.

Calculator at: Compressed Air Flow Chart | Compressed Air Systems | Selecting Compressed Air System

Actual results were: 9.46 CFM which gives 0.2678774 CM/M

blinded by the science. i would have shoved the airline in a frog,s rectum and timed how long he would take to explode. mind you, that's also a rough gues, as it depends on the amount of garlic and snails that the frog has consumed at his last meal. :biggrinjester:
b

 

[MarkieSparkie]

If you wish to calculate it by hand Rob:
The simplified equation is
Q=S x V (m[SUP]3[/SUP]/s)
where:
Q is the Flow Rate (m/s)
S is the Flow Area of the pipe (m[SUP]2[/SUP])
V is the velocity (m/s)

More precise calculation requires the full form of the Bernolli equation, the simplified version is only really true for incompressible flows (eg. most liquids), but it gives a reasonable approximation in most cases.