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shnabz

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A 230V, single phase machine, draws a current of 10A at a power factor of 0.8. Calculate the power dissipated by the machine.

Is the answer 12.5A?
 
P = I x V ( 10 x 230 = 2300W or 2.3kw )

2300/0.8/230 = 12.5A

P = I x Pf x V ( 12.5 x 0.8 x 230 = 2.3kw )

I = P / V ( 2300/230 = 10a )

My answer is 2300w but I've been up since 4am :( I'm sure someone more knowledgeable will pop by shortly.
 
Last edited:
P = I x V ( 10 x 230 = 2300W or 2.3kw )

2300/0.8/230 = 12.5A

P = I x V ( 12.5 x 0.8 x 230 = 2.3kw )

I = P / V ( 2300/230 = 10a )

My answer is 2300w but I've been up since 4am :( I'm sure someone more knowledgeable will pop by shortly.

That's because you did 12.5 x 0.8 x 230. Instead of 12.5 x 230
 
Has anyone been shown the fluorescent light example at college, with the PF correction cap being switched in and out of the circuit?

What will happen when it is switched out of circuit therefore giving it a power factor lower than unity?
 
Has anyone been shown the fluorescent light example at college, with the PF correction cap being switched in and out of the circuit?

What will happen when it is switched out of circuit therefore giving it a power factor lower than unity?

It would probably draw more current
 

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