S
santidreamer
The PSSC of a final ring circuit is 2KA so what is the min CPC size?
For PVC singles k = 115
CB 32A (BS EN 60898) will disconnect in 0.1 second
Fault current of low impediance = 2000A
S = square root of PSSC x PSSC x disconnection time (t) / Cable constant (K)
CPC size = 5.50mm (6mm cable)
So 2 x 1.5mm commonly used in final ring circuits is too small!
Earth fault loop impediance (Zs) is 0.4 Ohm (below the 1.5 ohm min)
By my calculations if an earth fault of low impediance was to occur anything less than a 6mm CPC would be damaged by the energy let through.
Should I now do as the regs say and consult manufacturers data for more accurate tripping times?
For PVC singles k = 115
CB 32A (BS EN 60898) will disconnect in 0.1 second
Fault current of low impediance = 2000A
S = square root of PSSC x PSSC x disconnection time (t) / Cable constant (K)
CPC size = 5.50mm (6mm cable)
So 2 x 1.5mm commonly used in final ring circuits is too small!
Earth fault loop impediance (Zs) is 0.4 Ohm (below the 1.5 ohm min)
By my calculations if an earth fault of low impediance was to occur anything less than a 6mm CPC would be damaged by the energy let through.
Should I now do as the regs say and consult manufacturers data for more accurate tripping times?