Hi Guys,
Is my understanding of why it is bad for a star/delta motor to be stuck in star correct?
1) Star delta starting is used as a method of starting larger motors at a reduced voltage of root 3 , which reduces the large starting current drawn by the motor during start up, therefore protecting the stator windings from burnout due to overheating. As the voltage across the motor windings are reduced by root 3 during starting in Star, this causes the line current drawn to be reduced to one third of the delta current.
As the torque will be reduced according to the square of the applied voltage; if the voltage is reduced by a factor of root 3, then the starting torque in star will be reduced by the square of the factor,therefore by a factor of 3, which reduces the starting torque to one third of the delta torque.
The power output of the rotor is also reduced to one third of a delta connected motor.
The design requirements of the motor is allow it to be started in star BUT run in delta, to match the required torque and power requirement of the driven load.
Therefore by running the motor in star means running the motor at one third of the torque and power output, meaning that the rotor will not match the required torque and power demand by the load, therefore the motor will stall and overheat.
Can you please pick out any technical inaccuracies in my answer.
Thanks,
Ewan
Is my understanding of why it is bad for a star/delta motor to be stuck in star correct?
1) Star delta starting is used as a method of starting larger motors at a reduced voltage of root 3 , which reduces the large starting current drawn by the motor during start up, therefore protecting the stator windings from burnout due to overheating. As the voltage across the motor windings are reduced by root 3 during starting in Star, this causes the line current drawn to be reduced to one third of the delta current.
As the torque will be reduced according to the square of the applied voltage; if the voltage is reduced by a factor of root 3, then the starting torque in star will be reduced by the square of the factor,therefore by a factor of 3, which reduces the starting torque to one third of the delta torque.
The power output of the rotor is also reduced to one third of a delta connected motor.
The design requirements of the motor is allow it to be started in star BUT run in delta, to match the required torque and power requirement of the driven load.
Therefore by running the motor in star means running the motor at one third of the torque and power output, meaning that the rotor will not match the required torque and power demand by the load, therefore the motor will stall and overheat.
Can you please pick out any technical inaccuracies in my answer.
Thanks,
Ewan