Working out the impedance of a circuit

[Humour_me]

Hi Guys,

Just wondering if anyone can give me a nudge in the right direction on how to work out the impedance of a circuit. The values I have to work with are that its and 230v ac inductive load circuit with a phase angle of 40 degrees and a resistance of 14 ohms.

I read and re-read my text books and just don't know how it would be worked out? Think I must be missing something obvious.

 

[Lister1987]

Ohm's law dictates V = I * R (R=Z for DC circuits)

At 40' you want to find out the voltage at that time so 230*SIN40 to get that.

Once you've done that you've got the V sorted out for the last part, and we know R = 14 ohms

Now we have snapshot voltage and resistance, we can get the current I = V/R once we have thst, we can plug it back into the original equation of: V = I * R and, if my maths is right, you'll have your answer

 

[Lister1987]

@Humour_me - Did you get anywhere with this?

 

[marconi]

Lister1987: well done for stepping in to help but you have misinterpreted the information that the phase angle in this LR circuit is 40 degrees. Have a rethink on what it is telling you. Hint - draw a circuit diagram, label it with the potential differences(pds) and current I and then draw a phasor diagram which combines these pds. Then think about how you would calculate these pds.