Discuss Any tips ?? Remembering formula in the UK Electrical Forum area at ElectriciansForums.net
Even though you may think they are a bit advanced just have a bash. a wise man once told me you learn best by making an a**e of it. get it wrong and we can show you where you went off the tracks get it right and that’s all good. How will you know if you never even try!Hey paddy I believe we are in the same position !
I started my level 2 in September and have been going over and over the theory as telectrix stated and believe it or not it does start to sink in
Maybe we could have some theory questions based on formula suitable for “level 2 students”
From some of the more experienced guys!
Just a thought.....
So far we have covered powers, ohms law triangle, power triangle, working out energy, work done, but the hardest for me is deffo transposition!
I have looked at some of the electrical design questions on the trainee section! But they are a little advanced for me at the moment!
But I still read it to get a flavour for real life scenarios
Even though you may think they are a bit advanced just have a bash. a wise man once told me you learn best by making an a**e of it. get it wrong and we can show you where you went off the tracks get it right and that’s all good. How will you know if you never even try!
Is it bad that I read that with the accentConfucius say, "If it too easy now, it bite you on arse later"
You need to take more care over details in engineering. 5kW what? Input? Output? a '5kW' motor, that would usually mean the mechanical output rating. A 5kW heater, that would be input power. Presumably 230 means 230V single-phase AC but you don't say that. 24A with what power factor or is this DC?
If I rephrase the question as:
A device uses 24A at unity power factor from a 230V single-phase AC supply and outputs 5kW useful power. What it its efficiency?
Now it can be calculated because I've filled in the missing info.
Input power = V.I.cos(phi)
Efficiency = useful output power / input power
=5000 / (230 x 24 x 1)
=91%
V=IR
I=V/R
P=VI
substitute I with V/R gives you ...
P=V * V/R = (V^2)/R
^2 is to the power of 2, ie V squared.
The variations in formulae are to account for the known variables.I see what you’ve done, but I don’t understand what you’ve done!
What’s the need to substitute I for V
In what situation would you use V2?
Flash cards. That's what I used. Have a Google, there's software that lets you make your own. It helps having a buddy so you can each test each other. I found it worked very quickly. I can't remember any of them now - well, apart from Ohms Law, and power.Hey I’m studying 2365 at college and I’m at the science part now .. any tips on remembering formula or is it just a case of going over and over it till it’s in your head .. any help much appreciated
Learn transposition.Hey I’m studying 2365 at college and I’m at the science part now .. any tips on remembering formula or is it just a case of going over and over it till it’s in your head .. any help much appreciated
the gender bender website will have all the info. .Learn transposition.
Reply to Any tips ?? Remembering formula in the UK Electrical Forum area at ElectriciansForums.net
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