And now a little puzzle

[the pict]

If any one like me has to do the full 18th course on line version from the NICEIC or if not here is a sample of the Challenges
A load of 750 watt 2 correction factors 1.03 and .65 what is the answer in Amps and how did you arrive at it, I will give my reasons later
Pict

 

[telectrix]

stupid question. 750 watts on single phase or 3? id single i get 4.8A

 

[the pict]

Single phase

 

[Loki]

750 / 230 = 3.2608695652

1.03 x .65 = 0.6695




edit

Ib = 3.2608695652
In = 6A

6/ 0.6695 = 8.9619118745

Iz = 8.96A

 

[davesparks]

A load of 750 watt 2 correction factors 1.03 and .65 what is the answer in Amps and how did you arrive at it, I will give my reasons later
Pict

This question makes no sense at all, I'm not even sure that there is a question here?
What do you want calculated, what voltage is this at, what do the correction factors relate to?

 

[Loki]

This question makes no sense at all, I'm not even sure that there is a question here?
What do you want calculated, what voltage is this at, what do the correction factors relate to?

Im assuming your finding Iz

 

[westward10]

You are not going to get a question which requires a calculation on the 18th Ed exam.

 

[the pict]

I will put up a screenshot of the actual question but will need to see about copyright, but basically the example equation was presented in an obscure manner as was the wording, whether or not this is meant to be "trick question" or an error I am not sure

 

[the pict]

Cg Ci, were the factors, the calculations were straightforward the presentation was not

 

[Silly Sausage]

If any one like me has to do the full 18th course on line version from the NICEIC or if not here is a sample of the Challenges
A load of 750 watt 2 correction factors 1.03 and .65 what is the answer in Amps and how did you arrive at it, I will give my reasons later
Pict

I would say, what is the apparent design current.
So, 750/230/1.03/0.65 = 4.87A

 

[Loki]

 

[Loki]

If using a 4A mcb then:


Ib = 3.2608695652
In = 4A

4/ 0.6695 = 5.9746079164


Iz = 5.97A

 

[buzzlightyear]

that in post #11 tells you how to apply cable calculations ,in 18th it will be multilabel choice exam.

 

[buzzlightyear]

Loki ,pdf if it on the forum and when any body stuck they can use that.

 

[Loki]

Loki ,pdf if it on the forum and when any body stuck they can use that.

Done


Cable Calculations - https://www.electriciansforums.co.uk/resources/cable-calculations.139/