Calculating R2 from R1 and RN

[telectrix]

indirectly, to be precise , rocker.

 

[IQ Electrical]

indirectly, to be precise , rocker.

Inversely to be precise Telectrix lol!

 

[telectrix]

OK IQ, as usual you are exactly correct. picky though. LOL.

 

[Sparky Ninja]

Just divide the big one by the small one. The difference in CSA is directly proportional to the difference in resistance.

Care to provide an example...

 

[telectrix]

i think what rocker means is divide the csa of the line conductor by that of the cpc to get the ratio of their respective reistances.

 

[Sparky Ninja]

So how would that work if we only had an (R1&R2) and not an individual R1 or R2 value?

I'll think this over in the morning.. sleepy time now me thinks.

 

[telectrix]

easy one . say we have R1+R2 = 2.35 ( hypothetical figure )

R2 = 1.67 x R1 ( 2.5/1.5mm )

so R1 + ( 1.67xR1 ) = 2.35

( 2.67xR1 ) = 2.35

R1 = 2.35/2.67 = 0.88

R2 = 2.35 - 0.88 = 1.47

( or R2 = 1.67 x 0.88 =1.47)