Csa

[ajelec10]

"two conductors of 6mm and 4mm are connected in parallel, thier effective CSA will be" ?

So asuming the guy ment to say the cables are 6mm2 and 4mm2 the effictive CSA of the two conductors in parrell would be 10mm2

Would you agree with that?

 

[Mac]

I think your wrong mate.6 squared is 36 and 4 squared is 16.To me that makes 52

 

[ajelec10]

Please are you winding me up. all cable sizes are given in mm2 this is the cross sectional area of the cable. you dont need to square them all you do is add them together
i cant make it any simpler.
Take two squares one with a base of 3 and a height of 2 the area of that square is 6
take anoter square base 2 height 2 area is 4
add the two square together you get a square with an area of 10, its the same with circles
could some one help me explain?

 

[Mac]

A=CSA r=radius d=diameter

A=r squaredxpi=d squaredxpi over 4=0.7854xd squared

 

[ajelec10]

Please explain your not making any sense?

i know its hard with no correct symbols

AJ

 

[Mac]

Sorry mate this is doing my head in.
6mm2 cable.CSA=pi 6 squared divided by 4=3.142x36/4=28.278
4mm2 cable.CSA=pi 4 squared divided by 4=3.142x16/4=12.568
I have had enough now.Think i'll dig my books out from 25 years agoThese are my final answers now

 

[stretchyboy]

I did look at the weblink you posted and it is for getting the wire csa from the diameter ..............

Where does it calculate two csa's added together. Do you really not understand that you just simply add csa together. Can you explain why you are adding the radiuses together? It doesn't make sense, it's not as if the two cables are melting together



You are adding diameter A to Diameter B and then working the cross section area which will give you the area of the big circle round the outside of the other two doesn't it?

 

[ajelec10]

Thank you strechy boy at least some one has some common sense

its a gcse maths question so simple!

Regards

Aj

 

[Mark.W]

So asuming the guy ment to say the cables are 6mm2 and 4mm2

But you can't just assume that is what he meant!. The black and white is that he wanted the csa of a 6mm conductor and a 4mm conductor.


Ok so after some investigation, I can see where stretchyboy is coming from in that you have to add the 2 csa's together. But then we have to agree that we have to calculate the csa of the condutors seperately and then add them together. Not add the conductors together then calculate the csa.

 

[ajelec10]

So if you go in to the whole saler and ask for some 6mm T+E what would you expect to get?
The csa of the phase and nuturals would be 6mm2 not 113.112,
We always refer to the cables as CSA not diemeter
Take some 25mm2 tails the diameter is not 25mm across is it!
Can we now agree please that the guy was talking about a 6mm2 and a 4mm2 and the effictive CSA of these two conductors are 10mm2

Regards

AJ

 

[andyb]

you are adding the cables together not adding the two radiuses together to make a bigger single cable though are you!

think about it.
You cant gain cross sectional area it would be like adding one football pitch to another football pitch and then saying that it was twice as wide and twice as long, therefore being the size of four football pitches

No stretchboy, if you add one football pitch to another football pitch you get twice the playing surface.

Just add the csa together, 6mm + 4mm = 10mm. (twice the surface)

 

[Mark.W]

So if you go in to the whole saler and ask for some 6mm T+E what would you expect to get?
The csa of the phase and nuturals would be 6mm2 not 113.112,
We always refer to the cables as CSA not diemeter
Take some 25mm2 tails the diameter is not 25mm across is it!
Can we now agree please that the guy was talking about a 6mm2 and a 4mm2 and the effictive CSA of these two conductors are 10mm2

Regards

AJ

He said 6mm CONDUCTOR and 4mm CONDUCTOR not cable, a conductor does not include the insulation, cos that would defeat the object.

The difference in opinion is you are assuming it to be 6mm and 4mm cable including the insulation, which then yes it would be 10mm.

However his question was a 6mm conductor and a 4mm conductor.....NOT CABLE.

If you go into the wholesaler and ask for 6mm and 4mm T&E then you are talking about the the CSA of the cable, The conductor size is the same as the wire diameter and in a 6mm cable it's 2.764 and in a 4mm cable it's 2.257. If he has said cables instead of conductors, then I would agree with you it's 10mm.

So the CSA of a 6mm CONDUCTOR (wire excluding the insulation) is 28.27 and the CSA of a 4mm CONDUCTOR (wire excluding the insulation) is 12.57

Regards
Mark

 

[andyb]

The csa of the conduct of 6mm cable is 6mm.

If you ask for 6mm cable in the wholesaler, that's what you get. Be it 6mm t&e, singles, swa, pyro or whatever, the csa is 6mm.

 

[Mark.W]

I understand that!

The wire diameter (Conductor) of a cable with a CSA of 6mm is 2.764. but what he asked for was the csa of the cable if the wire diameter (Conductor) was 6mm

I'd love to see a 6mm conductor go into a 6mm cable.

The OP asked for the CSA of a 6mm conductor and a 4mm conductor.

 

[ajelec10]

But surley you can see he means cable no?