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C

costanza

Just a little help if anybody wouldn't mind. I'm currently struggling with a theory.

I was taught that in transmission the greater the voltage, the smaller the current. Hence the high voltage used.

What I can't understand is how this rule applies when transforming a 230v supply to a 110v for use on a building site etc. Surely that would increase the current and make things worse?!
 
For transmission you are talking about transmitting power ie watts, therefore watts=current x voltage. As you say the higher the voltage the lower the current required to transmit the same power.
On a building site 110volts is safer because current=voltage/resistance. Therefore the resistance of a body would draw slightly less than half the current at 110volts as it would draw at 230volts.

Hope this helps.
 
To answer your question regarding building site transformers, voltage and current relationship Formula for transformer voltage and current relationship is

V1/V2 = I2/I1 VI = 220 VOLTS. V2 = 110 VOLTS LETS SAY I1 = 5 AMPS THEN

I2 = VI X I1/V2 = 220 X 5 / 110 I2 THEN = 10 AMPS

half the voltage you double the current. I work on high voltage transmission up to 400kv A 400kv transmission line can handle 3500 amps, operating at 3 phase.
The line can then carry 2400 Megawatts
 
Building site transformers are also centre tapped. So the voltage from live to earth (or neutral to earth ) would only be 55v.
spot on olly. 110v between L&E would be too great for safety on site. the centre tap on the secondary winding is earthed, so you have 55-0-55. and costanza, the current is higher at 110v, but that is not the issue. reducing the voltage is purely a safety issue.
 
Last edited:
Thanks for your help guys.

However there are two differing opinions here if I'm not mistaken.

So current = voltage/resistance...that would make the current smaller in a 110v than a 230v system.
 
In a 110v system the current required to supply the same power would be higher because
power(watts)=current x voltage. However if you have a constant resistance, such as a human body, and you put a voltage across it the current it draws is less as the voltage decreases because current=voltage/resistance.
I hope this explains why 110v, or as the others have pointed out 55v-0v-55v, is safer if you were to have a shock from it.
 
Last edited by a moderator:
Thanks for your help guys.

However there are two differing opinions here if I'm not mistaken.

So current = voltage/resistance...that would make the current smaller in a 110v than a 230v system.
no. for the same amount of power (watts). watts = voltsxcurrent, so if you halve the volts, you double the current.
 
At the college where I lecture part time there are 5 full time lecturers.
1-Only does part time courses
1- Is NVQ EV and so has no time to teach
1-Is an absolute dinosaur who hasn't seen a building site in 40 years
1-Is an electronics obsessive
1-Is actually a photocopier repair man by trade

It's factors like this that make my students prefer and request me the following year.
 

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