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Discuss Earth continuity in the Periodic Inspection Reporting & Certification area at ElectriciansForums.net

OP is saying he's testing at CU with ends disconnected, no appliances or loads connected.

But HandySparks is saying that if he had two water heaters spaced apart then there would be two cpc connections along with copper pipework connecting between, so these would reduce the resistance of the cpc (by effectively making a parallel cpc path) even with both ends disconnected at the distribution board.
 
But HandySparks is saying that if he had two water heaters spaced apart then there would be two cpc connections along with copper pipework connecting between, so these would reduce the resistance of the cpc (by effectively making a parallel cpc path) even with both ends disconnected at the distribution board.
Dunno, think the OP is saying no such heaters present?
 
Dunno, think the OP is saying no such heaters present?

Perhaps. But depending on what is connected and how (e.g. with dual boxes creating connections to other circuits' cpcs) it is possible for there to be parallel cpc paths, although not near as likely as on a job with steel containment obviously!
 
Perhaps. But depending on what is connected and how (e.g. with dual boxes creating connections to other circuits' cpcs) it is possible for there to be parallel cpc paths, although not near as likely as on a job with steel containment obviously!
Yep you could be right, perhaps the OP can confirm.Still think the RFC quite large, unless the whole property has only one RFC, or it's just big?
 
OP is saying he's testing at CU with ends disconnected, no appliances or loads connected.

Maybe not applicable to this case, but I was just replying to tel's implication that disconnecting the CPCs from the board would be enough to eliminate parallel paths when measuring r2 on a ring.
 
See my earlier post. If the heating is a gas boiler and fed from the RFC, and the gas supply is bonded, this may be the parallel path?
Yeah I did see your post my friend, and of course agree, but don't think it is in relation in this case, good shout though, I accept your view if there would be a boiler in the circuit as you have suggested.
 
Maybe not applicable to this case, but I was just replying to tel's implication that disconnecting the CPCs from the board would be enough to eliminate parallel paths when measuring r2 on a ring.
Well in general tel is correct, I agree it isn't always the case but he has a point.
 
Out of curiousity what is the formula for calculating length of run? Cheers

Table I1 in the On-Site Guide (p190 in the yellow one) gives resistance per metre (for a single conductor, e.g. end-to-end on a ring) and (R1+R2)/metre (if using method 1 for continuity of protective conductors).

The row that says "1.5" then a "-" is the resistance per metre of your cpc: 12.1mΩ
The row that says "2.5" then a "-" is the resistance per metre of your live conductors: 7.41mΩ

To work out the theoretical length of the cable (based only on measured resistance) you take your measured resistance and divide by one of those numbers. You can either convert your measured resistance from Ω to mΩ, or convert the above numbers from mΩ to Ω, or just use both numbers "as is" and multiply the answer by 1000.

So: ( 0.8 / 7.41) x 1000 = 108m (for your L and N end-to-end),
and: ( 0.6 / 12.1) x 1000 = 49.6m (for your cpc)

If 108m seems a bit long for your RFC, then a couple of poor connections on your live conductors is more likely.

If 50m seems a bit short for your RFC, then a parallel path on your cpc is more likely. This might be supplementary bonding, two water heaters / boiler connection, or even something bizarre like a switched FCU that forms a link between the two legs of the RFC about half way round when switched on (but not when switched off), and will always form a link for the cpc (I have seen a level 2 student terminate a S-FCU like this, bless!).

Handy reference for resistance/m:

1.0mm: 18.1 mΩ/m
1.5mm: 12.1 mΩ/m
2.5mm: 7.41 mΩ/m
4.0mm: 4.61 mΩ/m
6.0mm: 3.08 mΩ/m
10mm: 1.83 mΩ/m <--- main equipotential bonding conductors (usually)
16mm: 1.15 mΩ/m <--- earthing conductor (often)
25mm: 0.727 mΩ/m

Handy reference for (R1+R2)/m

1.0+1.0mm: 36.2 mΩ/m <--- older lighting radials (and sometimes strappers, e.g. with 3x1+1mm)
1.5+1.0mm: 30.2 mΩ/m <--- standard lighting radials
2.5+1.5mm: 19.51 mΩ/m <--- standard socket radial (protected by 20A OCPD)
4.0+1.5mm: 16.71 mΩ/m <--- standard socket radial (protected by 30A or 32A OCPD)
6.0+2.5mm: 10.49 mΩ/m
10+4.0mm: 6.44 mΩ/m
 
OP says #21 that it is a new property, so we assume new wiring, so likely also new (possibly cheap) sockets which could be giving poor connection on L & N

I thought his reading was based on the end-to-end resistances, which wouldn't be affected by the socket contacts. Presumably the actual terminal screws are tight in the socket outlet.
 
I thought his reading was based on the end-to-end resistances, which wouldn't be affected by the socket contacts. Presumably the actual terminal screws are tight in the socket outlet.

I think he means that the terminals on the sockets may be of poor quality i.e don't clamp down well. That Would most definitely affect end to end results, however, to have both line and neutral readings exactly the same rules that out bar an absolute freak circumstance.
 

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