Fans and ohm's law

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I am hoping for some advice on powering a 12v computer fan from the mains. I'm not an electrician, just doing a humble diy project.

The manufacturer states the fans actual input power is 1.6 W, with a maximum rated input current of 0.20 A. So, I believe I ideally need a current of 0.13A (1.6/12).

I'm hoping to achieve this with a 12v DC led driver. My issue is most of these provide far greater than 0.13A. I assume excess current above the 0.2A max will kill the fan.

Can this be solved with a simple resistor? I have a led driver rated at 12V and 1.66A. What resistor is necessary to meet the correct ampage and dissipate this much power?

Many thanks for any help
Ed
 
I'm not an electrician, just doing a humble diy project.
Yes, I can see that!
The rating of the power supply is the maximum current that it can deliver. The fan will just take 0.13A and that's what will get provided by the power supply. It's like your car, it is capable of doing 130MPH, but you drive it at 30mph. You do not need a giant flywheel to get rid of the excess 100mph!

Just make sure that the voltage is correct and that your driver is a constant VOLTAGE driver and not a constant CURRENT one.
Sorted?
 
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Thanks, a good analogy. So in short I do not need to worry. Out of curiosity, how does the circuit know the desired current? I may decide to drive at 30mph, but what limits the current in this situation?
 
The resistance of the fan's windings.

Its Ohms Law. V=IR so I=V/R so the greater the resistance is, the lower the current will be.

Revision here
Thanks for the link. The bit that throws me is the voltage is fixed at 12v and the resistance of the motor is fixed, based on the number of coils and wire gauge. Wouldn't ohms law imply the current also has to be fixed?

you will need to shunt the extra current around the fan,
do you know the maths to work it out ?

No. Any help would be appreciated!
 
If you're going to use an LED power supply I'd suggest a constant voltage supply rather than a constant current type.

I think that you're going to have an opposite problem if your power supply is too large. Electronic power supplies have a minimum load requirement for the output circuitry to give a stable voltage and often this figure isn't stated on the supply itself, you've got to go digging in the manufacturers spec sheets to find it.

If you use a power supply that's too big it won't cause too much current in the circuit, as already mentioned the current that will flow is governed by the impedance (resistance) of the item connected so it won't damage the fan motor but it might mean it won't give 12V and the fan simply won't run.
 
you need a 2A , 12V power supply. not sure if your fan is A.C. or D.C. though. the plug'in PSU you get with a netgear router will do if it's D.C..
 
you will need to shunt the extra current around the fan,
I really do not understand this. The fan will draw the amount of current commensurate with its resistance.
Where does this extra current come from???
If you put a shunt across the fan then the resistance decreases and the current drawn from the power supply will increase BUT the amount of current flowing through the fan will remain the same because
1. the voltage will still be 12volts
2. the resistance of the fan will not have changed.

Please, @dmxtothemax explain to me why the elecrtrical networks in your world are different to everybody elses
 
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who the hell mentioned the word shunt? that's a red sardine if i ever saw one. plug the fan into a car battery. clamp the current, get a psu a bit > the current drawn. NEXT?
 
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