Hi,
I have a lighting circuit which trips the RCD, I’ve got pared back so that if I take one brand new light fitting and wire it directly into the consumer unit with a brand new cable - and still the RCD trips. If I remove that wire from the consumer unit and put a 3 pin plug on it, and plug that 3 pin into the mains rings, one sockets ring works fine and the other trips out.
The lighting ring is a 6A MCB and the socket ring that also trips out is a 32A MCB, both on the same RCD; the socket ring that does not trip out is also 32A, but protected a separate RCD in the same CU.
The CU was brand new a few months ago (not fitted by me, it’s a properly certified installation) and came fully populated. Total current draw at the main fuse is around 2A so the MCBs are definitely not overloaded.
How is this possible? Dodgy RCD?
Thanks
John
I have a lighting circuit which trips the RCD, I’ve got pared back so that if I take one brand new light fitting and wire it directly into the consumer unit with a brand new cable - and still the RCD trips. If I remove that wire from the consumer unit and put a 3 pin plug on it, and plug that 3 pin into the mains rings, one sockets ring works fine and the other trips out.
The lighting ring is a 6A MCB and the socket ring that also trips out is a 32A MCB, both on the same RCD; the socket ring that does not trip out is also 32A, but protected a separate RCD in the same CU.
The CU was brand new a few months ago (not fitted by me, it’s a properly certified installation) and came fully populated. Total current draw at the main fuse is around 2A so the MCBs are definitely not overloaded.
How is this possible? Dodgy RCD?
Thanks
John