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Just finished written and online 2395. Passed online with 90%, found the written pretty hard. Anyone else done it today.
 
just done the written as a re sit. i had to put in loads of revision so hopefully went well? had a couple of "brain farts" but after checking my notes i'm ok. thought i new enough to get away with just a little revision last time, that cost me ÂŁ120!!
best bit of advice to anyone else doing it, download and read the examiners report its available to all and gives solid advice.
 
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just done the written as a re sit. i had to put in loads of revision so hopefully went well? had a couple of "brain farts" but after checking my notes i'm ok. thought i new enough to get away with just a little revision last time, that cost me ÂŁ120!!
best bit of advice to anyone else doing it, download and read the examiners report its available to all and gives solid advice.


How did you work out volt drop question ?
 
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sat the written tonight also think it was easier than the 2394 i took in december

volt drop question should has been 9.2 volts 0.23 ohms*40amps= 9.2 volts (ohms law)
 
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Whats a 1.2 correction factor when calculating volt drop ?

Can anyone post the question up ?

I take it from some of the repies that you have a value for either Rn or R1 doubled it and multiplied by the protetive device to get your answers!

I did my 2391 over 10 years ago, this never came up once!
Was mentioned on a recent thread, think you're getting confused with resistance testing.
 
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I can't remember the question word for word but it was something like this, you have combined line resistance of 0.23 and a load of 40amps calculate the voltdrop? I went for 0.23x1.2x40=11.04Vd . 1.2 for the correction factor for the operating temperature at 70·
 
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