V
VMan
Hi Guys,
Just reading through my spam and got an email for a voltage optimiser - claiming to save you money by reducing the voltage!!!
MyPlanet Voltis Voltage Optimiser
To me this is bull, if something need 1kW to work then it will consume 1kW..no?
My Math example:
At 240 volts:
1000watt appliance = 240 volts x 4.16Amps (240 / 4.16 = 57.7ohms)
My said appliance is heating a said volume of water and needs 1kw to boil. i.e 1000Watts for one hour
------------------------------
if i put a voltage reducer to 218V
At 218 Volts:
( V/R = I ) 218 / 57 = 3.77Amps
(P = I x V) 3.77 x 218 = 821.86 watts - ok customer maybe convinced and may buy one.
Now my said appliance still needs to boil the same amount of water, and will need the same amount of energy.
So 1 hour of the appliance on will only heat the water to 82% of needed value. there for will need to be on a total of 73mins to heat said water (deliver 1kW of energy to the water) - well maybe a bit more due to heat losses whilst heating the water.?!?!
so 1 Kwh will still be 1kWh regardless of voltage?!?!?
Am I right or wrong? or can anyone else explain how this may work -
(I believe a kW meter does not record Power factor(where a k/VA meter will) so even the power factor bull isn't right here.)
cheers
Just reading through my spam and got an email for a voltage optimiser - claiming to save you money by reducing the voltage!!!
MyPlanet Voltis Voltage Optimiser
To me this is bull, if something need 1kW to work then it will consume 1kW..no?
My Math example:
At 240 volts:
1000watt appliance = 240 volts x 4.16Amps (240 / 4.16 = 57.7ohms)
My said appliance is heating a said volume of water and needs 1kw to boil. i.e 1000Watts for one hour
------------------------------
if i put a voltage reducer to 218V
At 218 Volts:
( V/R = I ) 218 / 57 = 3.77Amps
(P = I x V) 3.77 x 218 = 821.86 watts - ok customer maybe convinced and may buy one.
Now my said appliance still needs to boil the same amount of water, and will need the same amount of energy.
So 1 hour of the appliance on will only heat the water to 82% of needed value. there for will need to be on a total of 73mins to heat said water (deliver 1kW of energy to the water) - well maybe a bit more due to heat losses whilst heating the water.?!?!
so 1 Kwh will still be 1kWh regardless of voltage?!?!?
Am I right or wrong? or can anyone else explain how this may work -
(I believe a kW meter does not record Power factor(where a k/VA meter will) so even the power factor bull isn't right here.)
cheers