What is an electric "amp"-? | on ElectriciansForums

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I believe "current" is the rate of flow
I believe "watts" volume of mass
I believe "volts" is the force
Then again I am not sure.

Then again all the above are means to measure something from different points of view while not understanding/explaining what "it" is.
 
I believe "current" is the rate of flow
I believe "watts" volume of mass
I believe "volts" is the force
Then again I am not sure.

Then again all the above are means to measure something from different points of view while not understanding/explaining what "it" is.

This may help
 
volts is an potential didfference, or electrical "pressure" between points. current will flow from 1 point to another (amps), matgnitude dependentt on impedance betweenthepoints. aas an analogy. a largeg bore water pipe will carry a largge volume of water. whereas a narrow pipe will restrictthe flow. (think of a thicker cable passing more current). watts is the actual power dissipated by the cable and the load., Volts X amps.
 
An amp is a certain number of electrons flowing in a certain time. If you want the exact numbers it's 6,240,000,000,000,000,000 electrons flowing per second.
 

This may help
Thank you for the link. I have created a link to review in the future. Now please do me a favor and look over the attached drawing. I have been told that it will not work and yet no one could tell me why. On a side note, this model could be scaled down.


You will need to scale the drawing down. The current scale is one to one.

wish you and yours the best today and forever more
 

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Thank you for the link. I have created a link to review in the future. Now please do me a favor and look over the attached drawing. I have been told that it will not work and yet no one could tell me why. On a side note, this model could be scaled down.


You will need to scale the drawing down. The current scale is one to one.

wish you and yours the best today and forever more

I somehow knew what this diagram would be, perhaps I am psychic.

What has it got to do with your original question re volts/amps though?
 
My suspicion is that someone has this idea that if we attached a "bubble" to a cable it will pull the cable up and the bubble will expand as it rises and the pressure drops. So all we need to do is keep creating those bubbles and we've a source of energy - which of course is the mythical perpetual motion machine as we'd need to put energy in to get the bubble down to depth in the first place, and losses would mean less out than we put in.

Or perhaps, the suggestion is that the "current" is not constant - if measuring by volume, the air current is lower at the bottom of the system than at the top. But that's because it's measuring the wrong thing - the mass is constant, but as it's compressible it changes volume.
 
Thank you for the link. I have created a link to review in the future. Now please do me a favor and look over the attached drawing. I have been told that it will not work and yet no one could tell me why. On a side note, this model could be scaled down.


You will need to scale the drawing down. The current scale is one to one.

wish you and yours the best today and forever more
You have been told repeatedly why it will not work, yes it will generate energy, which will be somewhat less than the energy needed to compress the gas to form the bubbles at depth.


It doesn't matter how many times you ask the same question, the answer is going to be the same.
 
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