OP
electricshock
No No Design current equals 1000 x kva divide it by square root 3 x line to neutral voltage.
So that's 75000 divide by 1.72 x 400
75000 / 688 = 109 amps
Grouping factor is 0.79 as there will be 3x 3phase circuits grouped together touching each other.
There is no ambient temperature factor as temperature will be aboutn room temperature and no insulation factor as it will be clipped direct to wall.
It will be protected by bs88 fuses, 1.25 fuse factor
Design current / factors
109amp/0.79x1.25= 110.37 amps
Volt drop can be only 5% of supply voltage for all except lighting which is 3%. So for 400v max volt drop 20volts.
Looking at table 4e4a I will need 25mm cable.
Volt drop for 25mm 3/4 core swa is 0.14 mv/a/m
I estimated about 30metres length so 30x110.37x0.14 = 463.55
463.55/ 1000 = 0.463 volts.
So that's well within the permitted volt drop.
I can't work out shock protection as I don't have ze value.
This guy is a menace! He needs physically stopping! He's going to kill someone one day!
electricshock, you are contravening BS 7671 by carrying on what you are doing without being competent to do so. You are also breaking the law as you are contravening The Electricity at Work Regulations 1989; regulation 16.
Stop what you are doing before you hurt someone and get a competent electrician to do the work, as you are not!
I for one cannot believe how so many people on here have helped this fella on his merry way, let alone been civil! I'm all for helping people to a certain extent, but this guy needs an education!!!
Calm down. I've connected dozens of machines without any problems.