I am filling in an EIC for the electrical installation with a light & a socket circuit for the newly built “Out-house” (garage conversion) and I have used the existing link from the main DB.
At the main DB -> Ze = 0.10 Ω , PFC = 4.0 KA and R1+R2 of the 2.5 mm link cable from the main DB to the Out-house DB = 0.32 Ω
Should I now assume that Ze at the Out-house DB is 0.10+0.32 = 0.42 Ω?, if not, how do I calculate Zs for the Out-house lighting circuit whose R1+R2 = 0.42 Ω
Again on the EIC which “DB’s” details should I enter for “Main Switch or circuit-Breaker” and “DISTRIBUTION BOARD DETAILS” boxes? Please refer to the pictures. I think main DB's details are not relevant here.
Many thanks!
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At the main DB -> Ze = 0.10 Ω , PFC = 4.0 KA and R1+R2 of the 2.5 mm link cable from the main DB to the Out-house DB = 0.32 Ω
Should I now assume that Ze at the Out-house DB is 0.10+0.32 = 0.42 Ω?, if not, how do I calculate Zs for the Out-house lighting circuit whose R1+R2 = 0.42 Ω
Again on the EIC which “DB’s” details should I enter for “Main Switch or circuit-Breaker” and “DISTRIBUTION BOARD DETAILS” boxes? Please refer to the pictures. I think main DB's details are not relevant here.
Many thanks!
