Does anyone know the Microsoft Excel 2010 formula entry to achieve the adiabatic equation?
Where, for example cell A1 is the prospective fault current, cell A2 is the disconnection time, cell A3 is the k factor and cell A5 is the resultant minimum c.p.c size?
Thanks
Spud
Hi
I should know the answer to this but i don't!
to find I for the adiabatic equation, which is the preferred option:
the example given by someone on this site says 230/Zs where Zs is found using Zs=Ze + (R1+R2)
the example in my book (BS7671 learning guide NICEIC) says 230/max earth loop...
Right guys.
Adiabatic equation, I want to work out if the swa armourings are adequate enough for the circuit, now it's a sub main feed from main Db, do I use the maximum fault current from origin or pfc at sub board, also do I use the protective protecting sub board.
Look forward to your answers
When plotting your PEFC against the times for your protective device in appendix 3 and your trying to work out an exact time, is it better to round it off to the nearest higher time frame?....As this will give you a slightly higher csa when working out your min acceptable size, which is better...
Anybody got their books handy, and feel like giving the old grey matter a work out?
Just finished a EICR on a school
200A TPN TNS system
Main conductors 95mm
Earth conductor 50mm
Bonding conductors 16mm
ZE-0.13
PEFC-1.78KA
PFC-3.56KA
is the bonding up to spec?, looks like its ok, but its...
Evening all,
I have a question regarding calculation of CPC on a 16mm T+E and wondered if you could help at all.
I have done a board change and the supply is via a 16mm T+E. It appears the CPC is 6mm and therefore I did the adiabatic equation to confirm if the CPC is adequate.
The circuit is...
Hi all,
been trying to work this out now and carnt get my head round some of the calculations.
please see where im going wrong.
voltage drop:
so 63amp mcb supplying electric boiler, run is approx 25 meters in 16mm twin & earth.
so Mv/a/m x length x amps divided by 1000= 2.8x25x63 divided by...
Hello all..
I have read some of the threads on the 'adiabatic equation' and still cannot understand it!
I have my assessor turning up on thursday to view my CU change, I have gone through everything with a fine tooth comb and am trying to cover everything he may find fault with. My ring main...
Maybe I'm overlooking the obvious but how would you calculate the min. csa of an earthing conductor of say a tn-s system when there is no time/current graph for a 1361 fuse in the BGB? Do you just obtain If from Uo/Ze and then use this in the adiabetic equation. Ta
I am trying to get my head around the Adiabatic equation and was hoping that someone could check my understanding?
I know the equation is S = √I² x t/k
S = the CSA of the CPC
I = the PFC which is calculated from Uo/Zs
t = now this is where I get a little confused, my understanding is...
This one has always made me wonder !??
Does this work as simply for a 3 phase installation i.e 3.3kw over 230volts = 14.3 amps
so does 3.3kw over 400volts = 8.8amps per phase OR is it 3.3kw over 230volts divided by 3 = 4.8 amps per phase ???
Can someone please explain where to get the time (t) in the adiabatic equation
i can work out the rest just need the (t)
the MCB is a BS 60898 63A
my PFC is 940A
Thanks
Hi all just been doing some adebatic equation most seem fine but im not sure on a few results could you help me out.
immersion heater.
230 volts divided by 0.30 zs = 776
776 squared X 0.1 = 60217
sqaure root 60217 = 245
245 divided by 115 = 2.1 S
Ive installed a 2.5mm t/e with a...
so you use the adiabatic equation to work out the cross sectional area of a conductor
the fomula is obviously S=(sq root) of I2xt/K
can someone give me some numbers so I can work out the answer useing this equation as I want to make sure i know how to do it.
Can somebody have a look at this and tell me which tree I'm barking up?
Using the Adiabatic equation to determine the required size of main bonding and therefore the size of supplementary bonding.
Ze = 0.18
PFC = 1.3 kA
Fuse type 1361 IIa
S = square root (1300 x 1300 x 0.1) /115
= 3.57...
doing pir before cu change. property built 1968 imperial size cable all test results ok. just one circuit is bothering me and i maybe looking into this too much but radial circuit, which originally was for an electric old type two bar fire as informed by owner who lived there since it was built...
Hi all,
Completed my first pir yesterday (: now this client has got a three phase supply, TNS which feeds a ground floor shop and a flat above, the flat has a on peak and off peak supply. With the tails for the flat going into two kmf switches with a sub main cable of only csa of 10mm T+E for...
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