14 new 9.5kw showers to be installed on existing supply

Hi Guys, ok, back to basics with a voltage dependant load, i.e. a shower which is purely resistive current is proportional to voltage so the higher the voltage, the higher the current, the higher the wattage. now with a voltage independent load, the wattage remains constant so the higher the voltage the lower the current etc, etc
 
Look at a basic 1kw load supplied at 250v, the current will be 4 amps yes! so using Ohms law 250/4=62.5Ohms, if voltage is reduced to 230v then 230/62.5Ohms= 3.68amps, so the new KW usage is KW=V*I so 230 * 3.68 = 846 watts, a saving of 154watts by reducing the voltage by 20volts. This formula will only work for a voltage dependant load, eg a shower.
 
please NO. that's be 87 posts.
 
at least they'll be clean worms with 14 showers to choose from
 
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Created
sparky351355,
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Dan,
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