431.2.1 again | Page 2 | on ElectriciansForums

Discuss 431.2.1 again in the Commercial Electrical Advice area at ElectriciansForums.net

I don't really understand what your point is? Your OP is about 4mm then isolator then 2.5 and now your on about 431.2.1 which is about having a neutral that's CSA is smaller than the line conductor.
 
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Ok let's rephrase . If calculations show that cable x should be used then how is it ok to use cable Y for the last few metres of this run . I'm not arguing I'm just posing a question that's all . If cable Y could be used for last few metres of said circuit then why are we using cable x for the first bit ?
 
Ok let's rephrase . If calculations show that cable x should be used then how is it ok to use cable Y for the last few metres of this run . I'm not arguing I'm just posing a question that's all . If cable Y could be used for last few metres of said circuit then why are we using cable x for the first bit ?

Probably to meet max Zs figures and permitted volt drop
 
YOu work out your cable calcs on the length and CSA of the conductors used, so if the first 50 meters is 4mm then the final 4 meters is in 2.5mm then you calculate it accordingly.
 
Now your confusing me how can voltage drop be better on a smaller cable at the end of a circuit . Maybe understand if other way round
 
OK ignoring the 431.2.1 reference which appears irrelevant.

If you have a circuit that start in a large csa and then drops to a smaller csa then it is likely that the designer was ensuring that the volt drop limits for the circuit were not exceeded, however you have said that volt drop is immaterial in an earlier post.

Your description of a 54m circuit in 2.5/1.5 would exceed the 11.5 V limit, however if half the circuit were run in 4/1.5 then you may just make the limit.
 
totally agree that you calculate on length and current carrying capacity but if total circuit length equates to using 4mm where and how do you calculate using 2.5 without fusing down at point of isolation .
 
totally agree that you calculate on length and current carrying capacity but if total circuit length equates to using 4mm where and how do you calculate using 2.5 without fusing down at point of isolation .

Then that's what you would use or a cable of a bigger CSA
 
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