OK here goes.....
√(34²-26.22²)=21.645
6
x10 ÷ 21.645=46200.0462
√(34²-26.22²)=21.645
6
x10 ÷ 21.645=46200.0462
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- Thread starter Simonslimline
- Start date
What are you trying to do there?
Trying to get a value for the capacitor needed, the 21.645 is divided by 10 to the 6 as the capacitor that will be needed will be in microfarads!
i am confusing myself to be honest
i am confusing myself to be honest
So, we worked out that the amount of reactive current that the capacitor needs to rectify is 26.22A right? You need to work out the ohmic reactive value of a capacitor that would allow 26.22A to flow through it. A tip.... Ohms law
The result of this calculation should give you an Xc value, one that you can then convert into Farads using other information available.
capacitor needed = 2x3.142x85x40.42(ohms) = 21589.9388/10 to the six = 46.3 micro farads. (hopefully)
Thanks for the help with that , much appreciated. 
Could you possibly post 1 with different values but the same scenario, i can work through it to make sure i can get the right answer without any help this time.
Could you possibly post 1 with different values but the same scenario, i can work through it to make sure i can get the right answer without any help this time.
What is the name of the programme you use to create your circuits by the way?
I'll get to work on one now
A capacitor of 51 microfarads hopefully
The power factor of the circuit is 0.79 Inductive.
I think i see where i went wrong..... 39.2 microfarads!
Hi everyone,
If...
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