Connect 25 AA batteries in parallel and series

[Malooq Omar Tariq]

To find out 6 ampere into milliamps, one ampere is equal to 1,00 milliamp, equation is mAh = Ah times 1000. 6 ampere to milliamps is 6 ampere times 1000 = 6,000 milliampere hours.

 

[Malooq Omar Tariq]

To work out energy, power = Energy divide by time. One watt is one joules. 3024 watts to joules is 3024 joules. Power = 3024 joules divide by 24 hours. 60 seconds in minute. 60 minutes is one hour times 60 seconds = 3,600 seconds. 24 hours is 60 minutes times 1,440 minutes. 1,440 minutes for 24 hours times 60 is 86,400 seconds. Power = 3024 joules divide by 86,400 seconds = 0.035 watts.

 

[Malooq Omar Tariq]

Power of one light emitting diode is 5 volts and 60 milliamp in watts. Ampere equation is Ah = mAh /1000.. 60 milliamp / 1000 = 0.06 milliamp. Power is I current in ampere and Voltage. Voltage 5 times 0.06 ampere = 0.30 watts for one light emitting diode. To work out current for fuse, current = power in watts divide by voltage. Power in watts is 3024 divide by 500 volts is 6.048, thus need to have 13 amp fuse.

 

[Malooq Omar Tariq]

To work out cost to run 100 light emitting diodes, you divide watts by 1000 to get kilowatt hour. 3024 watts total for one hundred light emitting diodes divide by 1,000 is 3.024. 24 hours is 86,400 seconds. Turn the 86,400 seconds into hours you divide by 3,600, that is seconds in one hour, total is 24 hours,

To work out cost for electric, you use power in kilowatt, 3.024 times time in hours, 24 x cost of one kilowatt, 11.871 from Gas & electricity prices per kWh - UKPower.co.uk - https://www.ukpower.co.uk/home_energy/tariffs-per-unit-kwh = 861.549696 in pence. 861.549696 into pounds is 861.549696 / 100 pence in one pound = £8.61 pence.

 

[Paul228]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.
Are you building a 100 LED light board and seeing if it's cheaper to run of batteries or stepped down mains?
Or are you looking to find the cheapest way to light your property?

 

[Malooq Omar Tariq]

£1.00 for twenty double aa batteries times 1.5 volts that is thirty volts. £10.00 is 200 aa batteries. 200 aa batteries times 1.5 volts is 300 volts. £5.00 times 20 aa batteries is 100 volts. £20.00 times 20 aa batteries = 400 aa batteries. 400 aa batteries times 1.5 volts = 600 volts.

600 volts into watts is P is power for watts = Volts 600 times I current in amps, 6 = 3,600 watts. To get watts into kilowatt hours, 3,600 divide by 1000 = 3.6 killowatts. 86,400 seconds in 24 hours, divide by 3,600 seconds in one hour, is 24 hours. Total cost is power in kilowatts, 3.6 killowatts x time in hours, 24 x £20.00 batteries = 1728 pence. 1728 pence, /100, 100 pence in £1.00 = £17.28

 

[Malooq Omar Tariq]

£20.00 Battery cost per kilowatt
£20.00 for 600 volts and 400 aa batteries. 600 volts times 2.20 amps = 1,320 watts. To get watts into kilowatt hours, 1,320 divide by 1000 = 1.32 killowatts. £20.00 divide by 1.32 kilowatts = 15.1515151515. £15.15 pence per 1 kilowatt, that is 1000 watts. 1320 watts times 2.20 amps is 600 volts.

 

[Malooq Omar Tariq]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.
Are you building a 100 LED light board and seeing if it's cheaper to run of batteries or stepped down mains?
Or are you looking to find the cheapest way to light your property?

I know that electric at 11.871 pence per kilowatt is £8.61 for 24 hours. Then, battery costs £17.28 for 24 hours. Electric for 24 hours, £8.61 - £17.28 for 24 hours from battery makes electric £8.67 cheaper. How do I buy a resistor that is 84 ohms and can handle 600 watts? Thanks for all your help. Enjoy your good week with your loving family and friends.

 

[Paul228]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

 

[Bob Geldoff1234]

As they say on Dragons Den....I'm out....

 

[Paul228]

Tell me why I don't like Mondays Mr geldoff

 

[Malooq Omar Tariq]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

I am not going to use electric power from electric power plug. I am going to use batteries, 400 aa batteries for £20.00 means 600 volts. To work out watts, 6 ampere times 600 is 3,600 watts. 500 volts for light emitting diodes times 6 ampere is 3,000 watt. 100 volts over and 600 watts over. Work out resistance, equation is R = V divide by I. R is resistance, volts 600 divide by 6 ampere = 100 ohms
Work out current in ampere, equation is I = V divide by R. I is current in ampere, 600 volts divide by 100 ohms = 6 ampere. How can I find a resistor that is 100 ohms and can handle 600 volts please?

Thanks for all your help. Enjoy your happy week and day with your loving family and friends.

 

[Paul228]

Why.
Just use less batteries or instead of wiring all 100 LEDS in series, try doing a combination of series and parallel wiring.
Take a look at this
LED circuit - Wikipedia - https://en.m.wikipedia.org/wiki/LED_circuit

 

[dmxtothemax]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

 

[Malooq Omar Tariq]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

Panasonic Eneloop AA pack 8 that have 1900 milliamp hours capacity. Total milliamp hours for 100 light emitting diodes in parallel is 6,000 milliamp hours because 60 milliamp for one light emitting diode times 100 is 6,000 milliamp hours.

Do you think that is better way for more energy in batteries that last a lot longer than alkaline aa batteries that run out of energy after a few uses?

Time that eight panasonic eneloop aa batteries power one hundred light emitting diodes

Eight Panasonic Eneloop AA batteries at 1.20 volts is 17,100 milliamp hours. 17,100 milliamp into amp is 17,100 milliamp divide by 1000 milliamp that is one amp is 17.1 amp hour from eight aa panasonic eneloop batteries. 6,000 milliamp from 100 light emitting diodes divide by 1000 milliamp that is one amp is 6 ampere. 8 AA batteries at 1900 milliamp hours are 17.1 ampere then divide by 6 ampere, that is one hundred emitting diodes means batteries last for 2.85, that is 2 hours and 0.85 times 60 minutes is 51 minutes. Panasonic Eneloop AA batteries cost £11.99 saving £8.01 in comparison to £20.00 worth of AA batteries that make 600 volts.