there is a we bit to observe and i am only learning it so sorry i cant help you as i dont fully understand it cause im a we fish in a big pond but i bark
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Discuss Help with three phase power in the Electrical Wiring, Theories and Regulations area at ElectriciansForums.net
which is why i suggested he got some expert help with the job. it may be to power motors or other industrial equipment. get it wrong and you're in it up to the neck. apart from that, public liability insurance may not cover him for 3 phase.
1.7 x cos o<i x pf
it's common. just a way for the insurance companies to screw more out of you.How many electricians check their insurance before every job to see if they are covered, would seem to be a stupid exclusion for an electrician
surely for design current
In = P/(400x1.732) = ?A
note: no power factor given
surely for design current
In = P/(400x1.732) = ?A
note: no power factor given
pure inductive load , and what about these super conductors in sern
Multiply 400 by 1.732 and you get 693.
Despite that the answer is right? Somehow?
:bucktooth:
my questioning comes from a lack of understanding on my part not questioning yours but as i was taught
Ib = P/(400x1.732xpf) example 10kW so 10,000/(400x1.732x0.8)= 18.04
selection of protective device
In= 20A
then It = In/rating factors ca cg etc
then on to VD
mVxIxLoR/1000
Oh come on. something that you freely admit you don't understand but you're still prepared to work on it and use that to further your knowledge?i dont understand 3 phase at all.... il have to start off like for like swaps and build on it...
Reply to Help with three phase power in the Electrical Wiring, Theories and Regulations area at ElectriciansForums.net