OP
suntrap
I'd use a washing machine mains filter, which have the current rating and can be bought cheap.
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Discuss Immersion Heater - PV electricity in the Central Heating Systems area at ElectriciansForums.net
I've been out of this thread for a few months while I followed the Nanode-based control solution that was discussed in earlier posts. I have done the assembly and mimicking and am about to connect to the 5V version of the same controller - MCPC2450A
pmcalli, do you have the output filtered? If so what have you used?
I have now completed testing of meter behaviour and have very bad news for you. The meter measures true power and your analog multiplier measures apparent power so you will be feeding back uneccesary power. I have now tested using a synchronous demodulator and it correctly follows true power as measured by the meter. The other advantage is the circuit is unchanged whether you use one ct on composite meter tail or two cts on seperate meter tails.
No, the bad news is the other way round. If you are just doing synchronous demodulation of the current waveform you are not using any voltage waveform information (other than the zero-crossing points), so you are assuming that its waveform is the same as the current. This is only true if you have a pure resistive load, which may not be the case.
As suntrap has pointed out already in posting #388, what I am doing is multiplying instantaneous current by instantaneous voltage and then averaging the result over (at least) one cycle.
That this will work with any load or combination of waveforms to give true rms power is a well-known mathematical result, if you are not familiar with it then read this paper
http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.134.5837&rep=rep1&type=pdf
or these articles
Power Measurement Article
Voltage, Current, Power & Energy : Definitions :: Electronic Measurements.
Any idea to the cause. I have stupidly been concentrating on trying to get true power when apparent power would actually have given some margin to this effect. On my systems I see the effect on both a two ct balanced system and a single ct on composite meter tail. In the 2-3 kW range most of the power is resistive so I can only speculate that either the current taps are non linear or the meter reads the composite waveform incorrectly. I will try the suggested analog multiplier but not hopeful as I have had previous bad experience (over 25 years ago mind ) with this device beacuse of non linearity effects of up to 5%?. I will also try my demodulator circuit with added hysteris in the mains voltage squarer this will give a selectable phase shift and hence give the same effect as miss balancing the two ct circuit which was very successful. I am desperate to get a solution to this as I have a queue of people whoose installer used a spare way in the consumer unit making a two ct design difficult to implement.I found found that to deal with the problem I have had to use two vairiable gain amps wich have allowed me to tune out the problem at the 2 to 3 kw point. I know 0.1 was only a small input but I didn't want to pull anything.
Many applogies I didn't read your post properly I mixed you up with another poster who is using an analog devices true rms device fed from current taps which will only deliver apparent power. Thanks for the links best explanation I've seen. However your statement is not 100% correct. If you synchronously demodulate the current waveform with the voltage zero crossings you do get true power. A simple simulation with sine waves out of phase proves this. What happens with non sine waves I havent analysed.
Can you remind me which analog multiplier you are using and I will try it out as a measuring device to identify the cause of my creep.
The I/P is filtered to stop fast turn on edge causing interference. I have used a standard emc filter from rs stock number 7024019.
That's OK, no problem, at least unlike the true rms converter your synchronous demodulation will give the direction of power flow. Perhaps I should have said a linear rather than resistive load, because I agree that this technique will cope with sinusoidal current out of phase with the voltage.
But I still think it will fall down if there is any harmonic current. Another way of thinking of it is that your square demodulation waveform contains odd harmonics (1/3 3f, 1/5 5f etc) which are not actually present in the voltage waveform, so if there is any harmonic current at these frequencies it will give corresponding spurious terms in the expression for power. This is probably addressed in the paper above but I confess I have not actually looked it up.
Interesting thing, that power halver, though I'd wait to see how much the 3kW one is as it would mean the standard/existing element could be used......
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