saint
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Why is the annual yield of a 2.15KWp system only about 1800 KWh's? What are the factors in this calculation?
Assuming 8hrs per day average = 2920 hrs per year.
2.15x2920=6278KWh
say 10% efficiency loss = 5650KWh
I'm lost!?
Assuming 8hrs per day average = 2920 hrs per year.
2.15x2920=6278KWh
say 10% efficiency loss = 5650KWh
I'm lost!?