M
Mr. Anderson
Maybe I did know it but it's gone now, so please refresh my memory.
You need an dedicated radial to the shed!
oops, sorry, I meant your customer needs a new radial.
Cheers, I will remember that.Now are you able to tell me how to work out the kW from kWh?
Now are you able to tell me how to work out the kW from kWh?
If you tried to google the manufacturers data you will see that the dryer alone is 10A
Just showing the OP that the information is easily available.
You were just guessing![]()
kWh = Power (in kilowatts) x time (in hours)
You do the rest...
If you tried to google the manufacturers data you will see that the dryer alone is 10A
Bosch WTW86561GB ? dryer with heat pump | User device manuals for AEG-Elektrolux, Asus, Apple, Bosch, Canon, Gardena, HTC, Husqvarna, MSI, Philips, Samsung, Siemens
I'm doubting my math now. To work out the amps when all I've got is the annual consumption I take the annual and divide by 365 (days) then by 24 (hours). This then gives me my watts per hour, I can then add up each appliance and divide by voltage to give me my total amps to find my breaker size?
Now that rings a bell, thanks! So (and this is from memory so I may very well not be getting this right) if E=Pxt then because I've already got the watts per hour then the math for the tumble dryer is...
E=Pxt
1.4kWh=1400x1
A=w/v
5.8A=1400/240
So then a 6A fuse should take that load. Obviously I have other loads to add to that in this situation BUT from what you guys are saying that seems very low?