BS-7671:2008:2011: Voltage-drop PS I will not type this out again
612.14. Verification of voltage drop
Where required to verify compliance with Section 525 , the following options may be used .
i) The voltage drop may be evaluated by measuring the circuit impedance .
ii) The voltage drop may be evaluated by calculations , for example , by diagrams or graphs showing maximum cable length v load current for different conductor cross-sectional areas with different percentage voltage drops for specific nominal voltages , conductor temperatures and wiring systems .
Note : Verification of voltage drop is not normally required during initial verification .
Written Examination 2395-302 Read the Qs) Good luck in Exams
Q/As 3 a) i)
Q) Explain the cause of voltage drop within an installation ( 3mk )
A) Volt drop is a product of the conductor resistance and the load current .
Com) The question refers to voltage drop that occurs normally within the installation which is caused by the conductor résistance and the current flowing , Do not confuse this with the causes of excess voltage drop due to poor design or overloading of the circuit
3 a) ii) State the two methods of determining voltage drop ( 2mk )
A) Measurement & Calculation
[h=4]Com ) it is not acceptable to carry out a direct measurement of voltage drop using volt meter(s) The circuit conductors must be at their normal operating temperature , the circuit under full load and there must be no variation in the supply voltage during the test , The methods given are as a result of the measurement of conductor résistance and the reference to charts or tables giving the details of voltage drop . These are not the figures in tables in Appendix 4 of BS-7671: which are generic design details for the calculation of appropriate cable sizes .[/h]
3) b) i) A radial circuit has a load current (Ib) of 28A at 230V ac and has a combined live-conductor résistance of 0.16Ω at 20°C .
Determine the voltage drop for this circuit , Show all calculations' ( 5mk )
A) Voltage drop = ( R[SUP]1[/SUP] + R[SUP]N[/SUP] ) x Ib x 1.2
So Voltage drop = 0.16 x 28 x 1.2 = 5.376V
Com ) The use of the conductor résistance and load current together with the 1.2 multiplier to compensate for the difference in conductor temperature at the time of test and the normal operating temperature of the conductors when maximum résistance and hence maximum voltage drop will occur .
3 b) ii ) if the radial circuit supplies a machine lathe , determine whether the voltage drop in b (i) above complies with BS-7671: ( 5mk )
A) Maximum volt drop - 230V x 5% = 11.5V ......... As 5.376V is equal to or less than 11.5V so complies
Com ) Alternative calculations such as : max voltage drop = 5% V drop = 5.376 ÷ 230 x 100 = 2.3% which is less than 5% So Ok
may be used and will attract the same marks .
(( 5.376 ÷ 230 = 0.023373913 x 100 = 2.3% ))
Tip . It is important to show the calculations because in this type of question where an error is made in the calculation candidates are only penalised once for the error .
The remainder of the answer is marked based upon the incorrect figure produced and , providing the process is correct , marked accordingly , Candidates could have completely the wrong answer for 3 b (i) but based upon their incorrect figure from that calculation achieve full marks for 3 b (ii ) providing their calculation and conclusion is correct .
GN-3 P/59 2.7.20. Verification of voltage drop . Section 525 .
612.14. Where it may be necessary to verify that voltage drop does not exceed the limits stated in relevant product standards of installed equipment BS-7671 : provides two options to do so , Where no such limits are stated , voltage drop should be such that it does not impair the proper and safe functioning of install equipment .
Voltage drop problems are quite rare but the inspector should be aware that long runs and / or high currents can sometimes cause voltage drop problems .
refer to GN-3 .