Tonight

[Knobhead]

Calculate the current at the five points in the network.

 

[Knobhead]

He couldn’t be that keen to learn about series parallel circuits.

OK my question looks a bit daunting but if approached in the right way it’s doable.

 

[Silly Sausage]

He couldn’t be that keen to learn about series parallel circuits.

OK my question looks a bit daunting but if approached in the right way it’s doable.

His brain has probably imploded.
If he's really clever he'll shove it into an online circuit analyser.

 

[HandySparks]

He couldn’t be that keen to learn about series parallel circuits.

Maybe if he'd used an appropriate thread title, rather than "Tonight", he'd remember where he left it.

I do wish members would use a title that actually related to the topic or question under discussion.

 

[Knobhead]

His brain has probably imploded.
If he's really clever he'll shove it into an online circuit analyser.

He could, but could he give the calculations that result in the five answers?

As I recall from my exams, showing the correct method of calculating was more important than the correct answer.

This is back in pre-historic days of written exams when electrical theory was taught instead of how to follow a crib sheet nailing bits of cable to a wall.

 

[Rockingit]

He could, but could he give the calculations that result in the five answers?

As I recall from my exams, showing the correct method of calculating was more important than the correct answer.

This is back in pre-historic days of written exams when electrical theory was taught instead of how to follow a crib sheet nailing bits of cable to a wall.

In fairness, you'd be hard pushed to accurately notate the workings out of that particular example as a reply on here.

 

[Knobhead]

Why not?

I’m drawing it out in colour to show each stage of the calculations to two decimal places. The drawings are going to take far longer than the calculations.

There’s even hints where I’ve asked for the current values. I should have asked for volt drop in the first question.

 

[Rockingit]

I'm not saying that the calcs are that hard, just that to replicate on a keyboard what you'd scribble out on a bit of paper is in itself a challenge.

 

[Silly Sausage]

Why not?

I’m drawing it out in colour to show each stage of the calculations to two decimal places. The drawings are going to take far longer than the calculations.

There’s even hints where I’ve asked for the current values. I should have asked for volt drop in the first question.

I'm tempted, for an occasion when I really can't be arsed doing anything else, to work that problem out in me head!

I forsee failing miserably!!!
I hope you've chosen friendly numbers.

 

[Knobhead]

Without the current at “A” nothing else can be calculated.

For parallel networks only two equations are needed R=1/((1/R[SUB]1[/SUB])+(1/R[SUB]2[/SUB])) for two resistors or R=1/((1/R[SUB]1[/SUB])+(1/R[SUB]2[/SUB])+(1/R[SUB]3[/SUB])) for three. Anything else the various networks are combined.

First calculate the two sub networks:

Add the two sub networks to give a single value:

We now have two parallel networks that have a resultant value:

Again by addition a total circuit resistance is given:

Good old Ohm’s law does the rest:

Its basic schoolboy maths and physics.










Or am I getting to old for this game?

 

[Silly Sausage]

Or am I getting too old for this game?

Going soft by the looks of it.
You being helpfull?!?! :smilielol5::smilielol5::smilielol5:

 

[Knobhead]

The first answers is in by PM a ½ hour before I posted the first section of answers.

From someone in Gods fair city of Nottingham.

I’ll keep adding bits to the calculations along with drawing over the next few days.

 

[Knobhead]

Going soft by the looks of it.
You being helpfull?!?! :smilielol5::smilielol5::smilielol5:

That's an ironic "thanks".

You should know me by now, if something interests me, I’ll get involved.

Obviously our OP isn’t interested but others are so it’s going to run for a couple of days.

I’ve got to do the drawings to follow the calculations. Rock reckoned I couldn’t get it in to an understandable format. I don’t think I’ve done too badly.

PM any answers, please don't spoil the teaching method.

 

[Silly Sausage]

That's an ironic "thanks".

You should know me by now, if something interests me, I’ll get involved.

Obviously our OP isn’t interested but others are so it’s going to run for a couple of days.

I’ve got to do the drawings to follow the calculations. Rock reckoned I couldn’t get it in to an understandable format. I don’t think I’ve done too badly.

PM any answers, please don't spoil the teaching method.

Fair enough. Good on you!
I'm trying to avoid your replies, don't want any hints. I reckon I can get half way until my mind melts down.

 

[Silly Sausage]

The first answers is in by PM a ½ hour before I posted the first section of answers.

From someone in Gods fair city of Nottingham.

Happysteve by any chance?