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Trainee questions to answer

Correct stu !

Well done mate !

Sorry if the drawing was not clear enough, thats just how the tutor at college had drawn it on the board so I copied it

Have you got a question to put up for the rest of us ?

Cheers
 
Right then, i was thinking of the circuit as being in series which is all ive seen so far so i thought the current was common but since its in parallel (which i have been reading up on all yesterday!) its the voltage that is common so i can use the 12v drop across R2 to give me the current at R1... so 12v / 4ohms = 3amps through R1

R1 + R2 = 5.4amps at R3

So the voltage drop across R3 is 5.4amps x 6ohms which is 32.4volts (hopefully!)

Yep, spot on.

Your turn to post a question
 
Correct stu !

Well done mate !

Sorry if the drawing was not clear enough, thats just how the tutor at college had drawn it on the board so I copied it

Have you got a question to put up for the rest of us ?

Cheers

Thanks! i'm looking for a question to post up now.
 
A question on resistivity as thats we have just been doing...

In the following exercise take the resistivity of copper as 1.78 x10-8 Ωm.


Find the cross sectional area of a copper conductor 42m long which carries a current of 36A with a voltage drop of 2.69v.
 
Hmm.. we have only just started looking at this the other night so dont think ill be able to get this one just yet, will have a read of my notes though and see if I can work it out ( doubt it though lol )
 
Hmm.. we have only just started looking at this the other night so dont think ill be able to get this one just yet, will have a read of my notes though and see if I can work it out ( doubt it though lol )

I found that one a bit tricky when we did these at college, if you struggle with it i can post up one of the example equations that we were given before we started the exercise as these were a real help when we were left to get one with questions.

Stu
 
I found that one a bit tricky when we did these at college, if you struggle with it i can post up one of the example equations that we were given before we started the exercise as these were a real help when we were left to get one with questions.

Stu


That would be much appreciated mate as im not sure how to work this one out

Cheers
 
That would be much appreciated mate as im not sure how to work this one out

Cheers

Not a problem... im sitting nervously trying to fill the time in til the derby kicks off, Sunderland v Newcastle at 13:30!!

Screen Shot 2013-10-27 at 12.56.44.png

Had to do a screen grab as it wouldnt let me copy and paste
 
Hi pennychew, we've just started this at college, so I'll give it a go! Is the answer 10mm2 cross sectional area? Cheers. Jim
 

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