When carrying out the continuity tests on the protective conductor of a circuit you will record either an R1+R2 or an R2.
You can use the result of this test to work out the length of the circuit using the resistance/meter values in Table 9A (page 166 OSG).
Once you have the length and design current of a circuit you can then work out the expected Voltage Drop using tables in the OSG or BS 7671.
As an example, let's say you have a 16A radial circuit wired in 2.5mm² T&E.
You do an R1+R2 test and record a value of 0.98Ω.
Now, using Table 9A in the OSG you can work out the length of the circuit.
From the table the resistance of 2.5mm² line and 1.5mm² cpc (R1+R2) is 19.51mΩ/meter.
So, if you divide the result of the R1+R2 test by this value it will give you the length of the cable.
0.98 ÷ (19.51 ÷ 1000) = 50.2 meters.
Now you have the length and design current you can work out voltage drop.
From Table 6D2 (page 130 OSG) the voltage drop per amp per meter for 2.5mm² cable is 18mV/A/m so total voltage drop would be (18 x 16 x 50.2) ÷ 1000 = 14.45V. The maximum voltage drop for power circuits is 11.5V(5%) so the circuit would not comply.
an excellent explanation, Jud, but surely, it's R1+Rn you need to use, not R1+ R2. so for example, you would use the figure of 14.82 as for 2.5/2.5mm.