If you have an RCD in place then the fault current only needs to be 30mA before disconnection takes place, at this current the 1667Ω resistance will only generate a 50V touch voltage which is the deemed safe level.
V= I * R = 0.03A * 1666.6666Ω = 50V
Thanks for the reply, yea that's a transposition of the R>50/Ia formula, but how does an RCD supplied live conductor come into contact with the extraneous conductive part that we are testing lets say a pipe?
I don't see how this relates to touch voltages, I thought that you would want any extraneous conductive parts to rise to the same potential as an exposed conductive part during single fault conditions so that a dangerous potential doesn't exist between the two - until ADS removed the fault.