Hi Im back after a heavy day with the kids ha. All this help is much appreciated.
Right so for question 1 I got R=V/I=3.58/2.5=1.432Ω A=Πxr²=3.142x1.432²=6.44A
And for question 2 I got R=V/I=11.5/13=0.88Ω L=RxA/P=0.88x2.5x10-6/1.72x10-8=
0.0000022/0.0000000172=127.9L
And for question 3 I got R=V/I=230/45=5.1 V=IxR=45x5.1=229.5V
Question 1 is after the CSA of the cable. Not sure why you have come up with a value in amperes?.
Question 2 Is very close to the answer i got, although i think i worked it out slightly different to the way you have.
Question 3 is incorrect. The VD is more than 0.5V. You need to work out the ohmic value from the information given and then multiply the current by this value to give you a value for volt drop.
Last edited: