Module 202 revision

[Chrisuk]

The voltage across B.
So, 15A through the top and bottom left 0.1Ohm and 5A through the top and bottom right 0.1Ohm
So dropping 2 * (15 * 0.1 + 5 * 0.1) = 4

Archy or anyone else with some grey matter, can you please explain this

if A is increased to 10A (not increased by 10) then surely A is 10A and B is 5A

i just dont understand why in your equation you have done 15*0.1 + 5* 0.1

15A is the total so how can you then do another 5A unless you thought it said increase A by 10, then it would give you 15A???

i would of thought the equation would be 15A (total) x 0.2ohms (total of right side) = 3V

HELP needed!!!!

 

[Silly Sausage]

Chris, if the current through A is increased to 10A, then the source is providing 15A in total, so 15A through the top & bottom left line resistances, and 5A through the other two.
Recall Kirchhoff's Law!!!