Point 1: I still maintain that the circuit can be overloaded on the N conductor, as no-one has proven otherwise with 3 off socket outlet circuits as the point of use.
Point 2: I'm not talking about PF, here either, we are at least talking harmonics & distorted N currents, which you cannot ignore.
Whilst the simplification I posted earlier I agree may have been a little "too" simple at 60A due to the 3 x 20A phase currents, no one has proven as yet that this cannot happen, & I don't believe that anyone can, when the final loads are unknown!

Point 1:
Without posting my sketches, I'm convinced that the max current that Neutral will carry is one phase loaded and the other two unloaded, as many have already said.

Point 2:
On a few 13A SOs, would that really come into play?
 
Well Archy, I'm not and no one has convinced me that the N cannot carry more than 20A without affecting the other circuits.
Also no one seems to be prepared to consider that the N current & voltage may not be in phase, nor that there may be no harmonics in the N current.
On a few 13A socket outlets yes I do believe it could come into play.

I'm not convinced & I still stand by the fact that the N currents can sum, and no one yet has proven otherwise, it is actually easy to prove they can, but I'm not here to do that.
 
Harmonics have got all the DNO's very worried these days, and for very good reason too!! Those 3 1/2 core cables they installed just about everywhere, are coming back to bite them in the arse!! Not quite the money saving solution they once thought them to be!! lol!!
 
Ok Paul, three phases (120deg out), three sockets (one on each phase), one common neutral. A 2.99kW light bulb (13A) is plugged into each socket. Will the neutral current sum to 39A?

Edit: LAMPS! I mean lamps, before you pedants jump on board! Lol.
 
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So you are drawing 52A per phase so it will sum to more than 39A.
Remembering that you have 2x2x13A socket outlets per phase & you are now drawing 13A per outlet, that is 26A per pair, thus the circuit is non compliant, however, you would hope that the circuit protective device would operate, to protect the conductors.

However, at 26A per phase how long would the MCB take to trip, if you were to only connect a single lamp to each twin socket outlet, and would the 2.5 be rated at this for a single phase, in its installed configuration, you would hope it was, and would there be no instances where it could be possible for the N to be overloaded, possibly not in a perfectly balanced loading scenario.

However, you cannot guarantee that this is all that will be connected.

I'm not going to do the maths at this time of night, sorry, I can see where you are coming from and it is possible for the N, not to be overloaded as the circuits could be perfectly balanced. though I doubt it.

Also, I'm now getting very tired and I'm getting to the end of the computer repair I'm doing tonight so it's time for bed as I'm up @ 06:00 in the morning for work.

This will have to continue the next time I am free to debate things.

However, I'm still maintain that the N CAN be overloaded.
 
No, three 13A lamps in total. A 13A load per phase in simple.

- - - Updated - - -

No, three 13A lamps in total. A 13A load per phase simply put.
 
OK, sorry missed the one per phase bit, read it as one per socket!
So currents will be reduced as per load reduction, the loads are now perfectly balanced (within reason) so the current drawn per phase will be say for arguments sake 13A
 
I'm not convinced & I still stand by the fact that the N currents can sum, and no one yet has proven otherwise, it is actually easy to prove they can, but I'm not here to do that.

You're pulling our chains now, bog standard 3 phase theory.
 
Fancy talk like non linear loads, reactance, harmonics and fancy things like that...I'm off down the pub.
 
OK, sorry missed the one per phase bit, read it as one per socket!
So currents will be reduced as per load reduction, the loads are now perfectly balanced (within reason) so the current drawn per phase will be say for arguments sake 13A

Forgive me if I'm wrong, but it does appear to me that you're being a tad evasive with your answers now. I know what the current per phase will be, what I want to know is what you believe the current in the common neutral will be at any given moment?

Would you be so kind as to answer the question with a simple A, B or C please:

A. The current in the neutral will sum to 39A.
B. The current in the neutral will be exactly the same as the current per phase (13A).
C. The current will be somewhere between 13A and 39A.


Secondly, what I would like to know is what you think the current in the common neutral would be if ONE of the 13A loads was then disconnected from one phase?

A. The current in the neutral will sum to 26A.
B. The current in the neutral will be exactly the same as the current per phase (13A).
C. The current will be somewhere between 13A and 26A.
 
Harmonics have got all the DNO's very worried these days, and for very good reason too!! Those 3 1/2 core cables they installed just about everywhere, are coming back to bite them in the arse!! Not quite the money saving solution they once thought them to be!! lol!!

Well it serves them right in not investing in the distribution system when they saw how the power requirements were changing, which will be borne, no doubt, by the tax payer. Every installation now relies on SMPs and almost all industrial sites uses VSD control.

I believe they call it CPD for their designers and workers.
 
Muesli, btw.
 
which I believe to be a linear load. Had it been eggs, well those currents can hang around for days.
 
Again just going to point out that this isn't actually my work! Didn't expect to see 8 pages of posts!
 
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3 sp circuits off a tp isolator
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