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O.S.G.. The use of other methods’ of determining Maximum Demand is Not Precludedwhere Specified by the Installation Designer

FirstlyI make no Apologies for the Way am Writing on any Matters . it can be a first day Apprentice or some one Needing aJog of Memory .
Sowe are all in the Same Boat . “ To Learn “

For the Apprentices . The Day we stop learning is the Day we hang Upour Tool-Bag

CookerDesign Current Calculations

Thefirst thing you have to do is get Your Head around the Calculations !!

(From a Design point of View ) 2392-10

DomesticInstallation Oven(s) & Hob(s) are to be Calculated upon their MAXIMUM LOADING
Startwith a simple Calculation ( An Oven has a rating of 2kW ) 2000

(I = P/V ) Formula … I = 2000 ÷ 230V = 8.70A …. Weare Using the Unit Amps


2392-10/ Domestic Installation Oven(s)

Ovenhas 4 Rings ( 2 x 1kW ) & ( 2 x 1.5kW ) & Grill ( 2kW ) & Oven (3kW )

-Controlled via a CookerSwitch with a Socket outlet .

Asa Designer . we’ll have to Apply Diversity ??

Important )- Diversity allowance to be Applied to the FULL LOAD CURRENT for CookingAppliances .

TheO.S.G. is telling us . Purpose of the Final Circuit fed from theConductors )
O.S.G.Table 1B p/97 – column (3) Cooking Appliances → At the Top of the Page Note : Type ofPremises ( 2392-10 → Household Installations ) Domestic Installation(s)

DomesticInstallation(s) Only O.S.G. - 10A + 30% f.l – Full Load ) of connected Cooking Appliances in the Excess of 10A+ 5A if a socket-outlet is incorporated in the Control Unit . ( C.C.U. ) – 45A + 13A Socket Switched with Neon .

Fromyour point of View ( The First 10A ofthe rated current plus 30% of the reminder ( Plus) 5A if the Control Unit incorporates s Socket.

Calculations)- You bank “ Hold OFF“ the first 10 Amps of the Maximum Load Current )
The10A will be used at the End of the Calculations’

-So your Work out the Total Power Rating & then calculate the Full Load Current

Calculations)- Power = ( 2 x 1 ) + ( 2 x 1.5 ) + ( 2+ 3 ) = 10kW

I= 10000 ÷ 230V = 43.48A … round it up to the first four numbers43.47826087 ( 48 ) 43.48A

UsingDiversity allowance stated ↑↑ ( 43.48A sub 10A = 33.48A )

I= 33.48 x 30 ÷ 100 = 10.04A

Youradding the ( 5A ) for Socket outlet . I = 10A + 10.04 + 5A = 25.04A )- Asa Designer this is your Expected Current Demand .

Remember )- Supply Cables Rated to suit DesignCurrent ( Iz ) :)
 

2392-10: Handy in yourExams . ( TT System ) ◄◄◄ :19:

Measuringusing Earth Electrode Test Instrument )

ThreeMeasurements are taken : 79Ω + 85Ω + 80Ω

Addedal Together ( 244Ω ) …………… 244Ω ÷ 3 = 81.33Ω

Why( 3 ) 3 / Rods . Yeah :chillpill:




 
2391-10: Ring Final Circuit . :26:

• Statethe relationship between Conductor length & Conductor Résistance .

Résistance. in Ohms , of a Conductor or Cable Increases with Length .


• InsulationRésistance . :yesnod:

Variationin Cable Length .

Asa Cable increases in length . unlike the conductor résistance which increaseswith length . Insulation Résistance decreases with length .

Theformula for calculating ( New Value ) of Insulation Résistance is as follows .

InsulationRésistance = Original length x InitialInsulation Résistance . / New Length

Example:

ACable of length ( 50m ) has an Insulation Résistancevalue of ( 200MΩ ) .
Ifits length is increased to ( 100m ) . Calculate its Insulation Résistance

InsulationRésistance = Original length x InitialInsulation Résistance . / New Length

=50 x 200 ---- 100

=10.000 ----- 100

= 100MΩ





 
Somethingto think about . Yeah . :yesnod:

Insulation Résistance

Statethe precautions to be . taken before testing Insulation Résistance in Terms of.

i)Isolation of circuit(s) & equipment .
ii)Voltage sensitive equipment .
iii) Electronic components .

a)Isolate of circuit(s) & Equipment .

1)Select a ( GS-38 ) ApprovedTest Lamp or Voltage Indicator .
2)Check ( Test /Lamp / Voltage ) indicatoris functioning correctly by testing on a ( Known Supplyor Proving Unit )
3)Determine whether Isolation is for ( Whole Installation or ( Specific Circuit(s) .
4)Locate means of Isolation ensuring there is no ( Standby Supply Arrangement )
5)Switch ( OFF & Lock OFF Isolation device(s)e.g. Fuses Switch . Isolator . MCB .
6)Verify . ( Using Test Lamp / Voltage Indicator. Circuit(s) are Dead between Line(s) Neutral & Earth.
7)Erect ( Warning Notice(s). in appropriate position(s) . 2392-10 . atConsumer Unit .
8)Re-check ( Test Lamps / VoltageIndicator ) is still functioning correctly .
9)Retain Key(s) . for Locking OFF Devices /

b) Before carrying out InsulationRésistance Testing it must beestablished that there is ( No Voltage Sensitive Equipment Connected ) thatmay be damaged or Malfunction because of the test voltage applied .

Examples:
Maybe Computers . Programmable Logic Controllers ( PLCs ) Programmers . etc. .

TheEquipment would either have to be disconnected during test . ( Testing / 612.3.3 ) ……….. PLUS – Note . Wherethe circuit includes Electronic Devices .

OrInsulation Test with Line(s) & Neutral connected together & Test between theses& the Protective Conductor .

c)Before carrying out Insulation Résistance Testing it must also be established that there is ( No Electronic Components ) that may be damaged ormalfunction because of the Test Voltage Applied .

Example - Dimmer Switch . This would have to beRemoved during test & the switch wires connected together .

- Describe Methods of Testing Insulation Résistance :

Beforecarrying out Insulation Résistance Testing ensure that . ??

1)All lamps . capacitors & loads are disconnected .
2)Voltage sensitive electronic equipment such ad Dimmer Switches . Touch Switches. Delay Timers . Power Controllers . Fluorescent lamps starter . Emergency Lighting . RCDs are disconnected .
3)There is No Electrical Connections between Line(s) . Neutral &Earth .



 
Useful Junk . ( If )

2392-10 :
RCD . the contacts will Automatically be Opened . Thereby providingagainst Electric Shock . The Term . “ RESIDUAL “ in Residual Current Device implies that ( There) is a residual current flowing in the ( Circuit )Over & above that required to provide ( Power to aLoad ) :yesnod:

 
2391-10 : ( This maybe helpful in Exams ) WORDING . Yeah :6:

612.2.1. Continuity ofProtective Conductors :

Protective Conductors .

Describethe need for . & Methods of . verifying the ( Continuity) of Protective Conductors & the “ Interpretation of results. ◄◄ :willy_nilly:

Answer

TheContinuity of the ProtectiveConductor is very important since it ( Forms Part) of the Earth Fault Loop Path .
Inthe event of a Fault to Earth the Faultcurrent flows through the Protective Conductors& the Earth Fault Loop Path as a whole .
Ifthe impedance of the Path was too high the Fault current may not be largeenough to operate the Protective Device thusresulting in ( Exposed Metalwork becoming Live )due to the circulating Fault current .




 
2392-10: :6:

Question.

InsulationRésistance . ( IR) Table 61 . :willy_nilly:

SELV & PELV (- upto ( 50V ) or ( 120V d.c. )

SELV ( Howdo I know / p/31 – Regulations . ) Extra – Low .


Describe the Test to Verify Separation between ( SELV ) circuits & other circuits ( -&-s )

SeparatedExtra Low Voltage ( SELV ) circuits operated at voltages up ( 50V ) or ( 120V d.c. ) This voltage can be obtainedin a number of ways such as a ( Double / Wound Transformer ) having a supply primary coil connected tothe 230V a.c. . Supply & an outputsecondary coil at the required Extra Low Voltage .
Thetwo coils are not & should not be connected in a ANY way 7 a test must be carried out to prove this .

Byusing an Insulation Resistance Tester . set to ( 250Vd.c. ) test voltage on the ( MΩ ) rangecarry out the following test procedure . With the transformer disconnected fromthe supply connected one test lead to the Primary coil & the Other testlead to the secondary coil .

Pressthe test button & note the reading in ( MΩ ) .

Tocomply with BS-7671:2008 . This reading should be no less than ( 0.5MΩ )
 
Apprentices:

Inspection & Testing . :coolgleamA:

Whatis the definition of Inspection .
Inspectionis a general term that can have a wide variety of meaning . Will usually bemore specific / VisualInspection or Non-destructive Testing .

GN-3p/63 . ( PIR )
621.2.
Theformal Inspections should be carried out in accordance with Chapter 62 ofBS-7671 . This requires an Inspection comprising careful scrutiny of the Installation. carried out without Dismantling or Partial Dismantling as required .together with theAppropriate Tests of Chapter 61 .

EarthFault Loop Impedance .
TheImpedance of the Earth Fault Loop . Line - to - Earth Loop . Starting& Ending at the point of Earth Fault .

RingFinal Circuit . Final Circuit arranged in the form of a Ring & connectedto a Single Point of Supply .

ResidualCurrent Device . ( RCD )

( Residual / Dual . meaning two . Line& NeutralTwo liveconductors .

ItUses the Idea that the Current in the Line &Neutral must be Exactly the Same . Yeah ( Balanced )

TheRCD does is compare the Current in the Line& Neural . If they’re not Identicalit Trips Out .


 
2392-10.

O.S.G.p/86
612.7. EarthElectrode Résistance . ( Ra ) - 200Ω

612.7. : Electrode underTest is being used in conjunction with an ( RCD)

A Loop Impedance Tester ( Zs )

TTSystem(s) . The value of the Earth Electrode Résistance ( Ra ) in Ohms. Multiplied bythe Operating Current in Amperes of the Protective Device . ( I∆n ) should NOTexceed ( 50V ) ( Ra ) = 200Ω . Then the maximum RCD operating Current should NOTexceed ( 250mA ) :coolgleamA:

 
Apreferred sequence of Tests is recommended . Where Relevant . 2392-10 :willy_nilly:

TN-S / TN-C-S .

612.2.1. Continuity of protective conductors .
612.2.2. Continuity of Ring Final conductors .
612.3.Insulation Résistance . ( IR )
612.6. Polarity .

612.7. Earth Fault LoopImpedance .
612.10. Additional Protection .
612.11. Protective Fault Current . ( PFC )
612.13. Functional Testing .
 
Last edited by a moderator:
2392-10.

Lets make the Books work for Us . O.S.G. p/166 . Table 9A .

612.2.1. Continuity of ProtectiveConductors .

AllProtective Conductors . including Main Protective Bonding Conductors &Supplementary Protective Bonding Conductors . ( Where Required )

ConductorSize ( mm[SUP]2[/SUP] ) 2.5 : Résistance ( mΩ/m ) 7.41 .
ConductorSize ( mm[SUP]2[/SUP] ) 4.0 : Résistance ( mΩ/m ) 4.61 .
ConductorSize ( mm[SUP]2[/SUP] ) 6.0 : Résistance ( mΩ/m ) 3.08 .

ConductorSize ( mm[SUP]2[/SUP] ) 10.0 : Résistance ( mΩ/m ) 1.83 .
ConductorSize ( mm[SUP]2[/SUP] ) 16.0 : Résistance ( mΩ/m ) 1.15 .


I WorkingLong Hours . Sunday is the Only DayOff .

I do Apologize if I make any Small Mistakes . Thank youfor Understanding . :willy_nilly:
 
ASimple Résistance test between the Ends of the Line . Neutral or Circuit Protective conductors willonly Indicate that a Circuit Exits .

Whetherthere are Interconnections or Not .

Same value whatever diameter is measured .

(L1 / N2 ) ↔ ( N1 / L2) Circuit formed by Cross- connection .

InitialVerification :
Aftercross connection of Line & CPC you’d check between Line & CPC at every Socket & Spurs would becomeApparent . ( Spur ) will give a Higher Reading .Ω


Apprentices: ( Firstly – You Reading confirms thatthere is No Open Circuit on the Ring Final Circuit) Yeah .

RingFinal Circuit . ( Dead Test )

Instrument: Set on Ohm’s .

Under(- Schedule ofTest Results .
CircuitLoop Impedance Ω
RingFinal Circuit / Only measured – ( End to End )

Line/ Line - Little ( r1 ) = 0.43Ω . Measured – ( Endto End ) Bigger Copper / Lower Résistance .
Neutral/ Neutral - Little ( r/n ) = 0.42Ω . Measured – ( Endto End ) Bigger Copper / Lower Résistance .

CPC/ CPC - Little ( r2 ) = 0.73Ω . Measured – ( End to End ) SmallerCSA / High Résistance


Topquark. I can’t Editany Post . on my Section(s) Thankyou . :coolgleamA:



 
OhmicValues (- 70m Ring Final Circuit . –wired in 2.5mm[SUP]2[/SUP] / 1.5mm[SUP]2[/SUP] Twin . T&E ) :willy_nilly:

Readings at Each Socket . Examples Only.

Measurements. L1 / L2 . 0.26Ω - ( 0.015Ω )
Measurements. N1 / N2 . 0.26Ω - ( 0.015Ω )

Measurements. CPC -1 / CPC - 2 . 0.32Ω & 0.34Ω . - ( 0.02Ω )

ForSpurs . each metre in length will add the flowing résistance to the above values.

 
Polarityis towards the end of the recommended test sequence . 612.6 :svengo:

Polarityon the Ring Final Circuit conductors is Achievedsimply by conducting the Ring Circuit Test .

Asfor Radial socket outlets . (- Continuity of the CPC will have already been Proved by linking Line& CPC & Measuring between the same terminalsat each socket .
OnlyLine / CPC reversalsneed to be Checked .

612.2.Continuity of Conductors . We are conducting this Test at the same time as thatfor Continuity of CPCs . ( In Theory ) :bulb2:

Wedo this for Ring Final Circuit . CPCs End – End
Wedo this for Radial . Line / CPC

( In Theory ) Radial Circuit . Line / CPC . we are using Wander Lead Return .

Linkingtogether Line & Neutralat the Origin & Testing between the same Terminals at “ Each SocketLine / CPC reversalwill result in NO Reading at the Socket inQuestion .

Lighting Polarity (- Link at Consumer Unit ) Line & CPC – Pendent Set . ( Polarity / proved by Operating Switch ) Switch wire / CPC . Switchis Opened & to confirm then Closed Polarity



 

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